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The area bounded by the curve y = log x and y = (log x)2 is :
  • a)
  • b)
    (3 - e) aq. units
  • c)
  • d)
    (e - 3) aq. units
Correct answer is option 'B'. Can you explain this answer?
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The area bounded by the curvey= logxandy= (logx)2is :a)b)(3 - e) aq. u...
To find the point of intersection,
log x = (log x)2
⇒  log x (log x – 1) = 0
⇒  log x = 0        or    log x = 1
⇒  x = 1, e
Hence, the required area will be  

= [e - e - (-1)] - [e - 2e + 2e - 2]
= 1 - (e - 2)
= (3 - e) sq. units
The correct answer is: (3 - e) sq.units
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The area bounded by the curvey= logxandy= (logx)2is :a)b)(3 - e) aq. unitsc)d)(e- 3) aq. unitsCorrect answer is option 'B'. Can you explain this answer?
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