Physics Exam > Physics Questions > Calculate under what pressure (atm) water wou...
Start Learning for Free
Calculate under what pressure (atm) water would boil at 150°C. If the change in specific volume when 1 gram of water is converted into steam is 1676cc. Given, latent heat of vaporization of steam = 540 cal/g; J = 4.2×107 erg/cal and one atmosphere pressure = 106 dynes/cm2
Select one:
Select one:
- a)3.628
- b)1.814
- c)2.814
- d)0.814
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
Calculate under what pressure (atm) water would boil at 150°C. If ...
Here, ∂H = 540 cal.
= 540 × 4.2 × 107 erg.
∂V = 1676cc
Boiling Temperature T = 373 K
Temperature when water is to be boil = 150°C
= 150 + 273 = 423 K.
∂T = 423 – 373 = 50 K
∂p = ?
Applying these value in the maxwell's thermodynamical relation
= 1.814 × 106 dynes/cm2
= 1.814 atmosphere
Therefore, the pressure at which water would boil at 150°C
= 1.814 + 1,000 = 2.814 atmospheric pressure.
The correct answer is: 2.814
= 540 × 4.2 × 107 erg.
∂V = 1676cc
Boiling Temperature T = 373 K
Temperature when water is to be boil = 150°C
= 150 + 273 = 423 K.
∂T = 423 – 373 = 50 K
∂p = ?
Applying these value in the maxwell's thermodynamical relation
= 1.814 × 106 dynes/cm2
= 1.814 atmosphere
Therefore, the pressure at which water would boil at 150°C
= 1.814 + 1,000 = 2.814 atmospheric pressure.
The correct answer is: 2.814
Most Upvoted Answer
Calculate under what pressure (atm) water would boil at 150°C. If ...
The boiling point of water is dependent on the pressure applied to it. At standard atmospheric pressure (1 atm), water boils at 100°C or 212°F. As the pressure decreases, the boiling point of water also decreases.
To calculate the pressure (in atm) at which water would boil at 150°C, we need to use a reference point. Let's use the boiling point of water at 100°C and 1 atm pressure.
Using the Clausius-Clapeyron equation, we have:
ln(P2/P1) = ΔHvap/R * (1/T1 - 1/T2)
Where:
P1 = 1 atm (reference pressure)
T1 = 100°C + 273.15 (reference temperature in Kelvin)
T2 = 150°C + 273.15 (desired temperature in Kelvin)
ΔHvap = heat of vaporization of water = 40.7 kJ/mol (at 100°C)
R = 8.314 J/(mol·K) (gas constant)
Plugging in the values:
ln(P2/1) = (40.7 kJ/mol) / (8.314 J/(mol·K)) * (1 / (100°C + 273.15 K) - 1 / (150°C + 273.15 K))
Simplifying:
ln(P2) = (40.7 kJ/mol) / (8.314 J/(mol·K)) * (1 / 373.15 K - 1 / 423.15 K)
ln(P2) = 4.903 - 4.580
ln(P2) = 0.323
Using the natural logarithm property:
P2 = e^0.323
P2 ≈ 1.381 atm
Therefore, water would boil at approximately 150°C under a pressure of 1.381 atm.
To calculate the pressure (in atm) at which water would boil at 150°C, we need to use a reference point. Let's use the boiling point of water at 100°C and 1 atm pressure.
Using the Clausius-Clapeyron equation, we have:
ln(P2/P1) = ΔHvap/R * (1/T1 - 1/T2)
Where:
P1 = 1 atm (reference pressure)
T1 = 100°C + 273.15 (reference temperature in Kelvin)
T2 = 150°C + 273.15 (desired temperature in Kelvin)
ΔHvap = heat of vaporization of water = 40.7 kJ/mol (at 100°C)
R = 8.314 J/(mol·K) (gas constant)
Plugging in the values:
ln(P2/1) = (40.7 kJ/mol) / (8.314 J/(mol·K)) * (1 / (100°C + 273.15 K) - 1 / (150°C + 273.15 K))
Simplifying:
ln(P2) = (40.7 kJ/mol) / (8.314 J/(mol·K)) * (1 / 373.15 K - 1 / 423.15 K)
ln(P2) = 4.903 - 4.580
ln(P2) = 0.323
Using the natural logarithm property:
P2 = e^0.323
P2 ≈ 1.381 atm
Therefore, water would boil at approximately 150°C under a pressure of 1.381 atm.
|
Explore Courses for Physics exam
|
|
Similar Physics Doubts
Calculate under what pressure (atm) water would boil at 150°C. If the change in specific volume when 1 gram of water is converted into steam is 1676cc. Given, latent heat of vaporization of steam = 540 cal/g; J = 4.2×107 erg/cal and one atmosphere pressure = 106 dynes/cm2Select one:a)3.628b)1.814c)2.814d)0.814Correct answer is option 'C'. Can you explain this answer?
Question Description
Calculate under what pressure (atm) water would boil at 150°C. If the change in specific volume when 1 gram of water is converted into steam is 1676cc. Given, latent heat of vaporization of steam = 540 cal/g; J = 4.2×107 erg/cal and one atmosphere pressure = 106 dynes/cm2Select one:a)3.628b)1.814c)2.814d)0.814Correct answer is option 'C'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Calculate under what pressure (atm) water would boil at 150°C. If the change in specific volume when 1 gram of water is converted into steam is 1676cc. Given, latent heat of vaporization of steam = 540 cal/g; J = 4.2×107 erg/cal and one atmosphere pressure = 106 dynes/cm2Select one:a)3.628b)1.814c)2.814d)0.814Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate under what pressure (atm) water would boil at 150°C. If the change in specific volume when 1 gram of water is converted into steam is 1676cc. Given, latent heat of vaporization of steam = 540 cal/g; J = 4.2×107 erg/cal and one atmosphere pressure = 106 dynes/cm2Select one:a)3.628b)1.814c)2.814d)0.814Correct answer is option 'C'. Can you explain this answer?.
Calculate under what pressure (atm) water would boil at 150°C. If the change in specific volume when 1 gram of water is converted into steam is 1676cc. Given, latent heat of vaporization of steam = 540 cal/g; J = 4.2×107 erg/cal and one atmosphere pressure = 106 dynes/cm2Select one:a)3.628b)1.814c)2.814d)0.814Correct answer is option 'C'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Calculate under what pressure (atm) water would boil at 150°C. If the change in specific volume when 1 gram of water is converted into steam is 1676cc. Given, latent heat of vaporization of steam = 540 cal/g; J = 4.2×107 erg/cal and one atmosphere pressure = 106 dynes/cm2Select one:a)3.628b)1.814c)2.814d)0.814Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate under what pressure (atm) water would boil at 150°C. If the change in specific volume when 1 gram of water is converted into steam is 1676cc. Given, latent heat of vaporization of steam = 540 cal/g; J = 4.2×107 erg/cal and one atmosphere pressure = 106 dynes/cm2Select one:a)3.628b)1.814c)2.814d)0.814Correct answer is option 'C'. Can you explain this answer?.
Solutions for Calculate under what pressure (atm) water would boil at 150°C. If the change in specific volume when 1 gram of water is converted into steam is 1676cc. Given, latent heat of vaporization of steam = 540 cal/g; J = 4.2×107 erg/cal and one atmosphere pressure = 106 dynes/cm2Select one:a)3.628b)1.814c)2.814d)0.814Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Physics.
Download more important topics, notes, lectures and mock test series for Physics Exam by signing up for free.
Here you can find the meaning of Calculate under what pressure (atm) water would boil at 150°C. If the change in specific volume when 1 gram of water is converted into steam is 1676cc. Given, latent heat of vaporization of steam = 540 cal/g; J = 4.2×107 erg/cal and one atmosphere pressure = 106 dynes/cm2Select one:a)3.628b)1.814c)2.814d)0.814Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Calculate under what pressure (atm) water would boil at 150°C. If the change in specific volume when 1 gram of water is converted into steam is 1676cc. Given, latent heat of vaporization of steam = 540 cal/g; J = 4.2×107 erg/cal and one atmosphere pressure = 106 dynes/cm2Select one:a)3.628b)1.814c)2.814d)0.814Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Calculate under what pressure (atm) water would boil at 150°C. If the change in specific volume when 1 gram of water is converted into steam is 1676cc. Given, latent heat of vaporization of steam = 540 cal/g; J = 4.2×107 erg/cal and one atmosphere pressure = 106 dynes/cm2Select one:a)3.628b)1.814c)2.814d)0.814Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Calculate under what pressure (atm) water would boil at 150°C. If the change in specific volume when 1 gram of water is converted into steam is 1676cc. Given, latent heat of vaporization of steam = 540 cal/g; J = 4.2×107 erg/cal and one atmosphere pressure = 106 dynes/cm2Select one:a)3.628b)1.814c)2.814d)0.814Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Calculate under what pressure (atm) water would boil at 150°C. If the change in specific volume when 1 gram of water is converted into steam is 1676cc. Given, latent heat of vaporization of steam = 540 cal/g; J = 4.2×107 erg/cal and one atmosphere pressure = 106 dynes/cm2Select one:a)3.628b)1.814c)2.814d)0.814Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Physics tests.
|
|
Explore Courses for Physics exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup