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Calculate the pressure (in atmospheres) required to make water freeze at - 10C. Change of specific volume when 1 gm of water freezes into ice = .091 cc.,J =4.2 x 107 ergs/cal..1 atmosphere 106 dynes / cm2 and the latent heat of ice = 80 cal./ gm.
    Correct answer is '136.2'. Can you explain this answer?
    Verified Answer
    Calculate the pressure (in atmospheres) required to make water freeze ...
    Given dT = 10C . V2 - V1 = -0.091 c.c.
    L = 80 cal. = 80 * 4.2 * 107 ergs, T = 0 + 273 = 273 K 
    Applying Clapeyrons latent heat equation

    or  dynes/cm2.

    = 135.2 Atmos.
    Hence to lower the melting of ice by 1°C, the pressure must be raised by 135.2 atmospheres.
    Now melting point of ice at atmospheric pressure is 0°C. Hence pressure required to make ice freeze at - 1 °C 
    = 135.2 + 1 = 136.2 atmospheres
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    Most Upvoted Answer
    Calculate the pressure (in atmospheres) required to make water freeze ...
    Given:
    - Change in specific volume when 1 gm of water freezes into ice = 0.091 cc
    - Latent heat of ice = 80 cal/gm
    - J = 4.2 x 10^7 ergs/cal
    - 1 atmosphere = 10^6 dynes/cm^2

    To find:
    Pressure required to make water freeze at -10°C in atmospheres

    Solution:

    Step 1: Convert the change in specific volume from cc to cm^3
    Given change in specific volume = 0.091 cc

    1 cc = 1 cm^3
    Therefore, change in specific volume = 0.091 cm^3

    Step 2: Convert the latent heat of ice from calories to ergs
    Given latent heat of ice = 80 cal/gm

    1 cal = 4.2 x 10^7 ergs
    Therefore, latent heat of ice = 80 x 4.2 x 10^7 ergs

    Step 3: Calculate the pressure required to make water freeze at -10°C

    The change in specific volume when water freezes into ice is given by the equation:

    ΔV = Vf - Vi

    Where:
    ΔV = change in specific volume
    Vf = final specific volume of ice
    Vi = initial specific volume of water

    Given ΔV = 0.091 cm^3
    Let's assume the initial specific volume of water (Vi) = Vw
    The final specific volume of ice (Vf) = Vi + 0.091 cm^3

    The work done during the expansion of water freezing into ice is given by the equation:

    W = PΔV

    Where:
    W = work done
    P = pressure
    ΔV = change in specific volume

    The work done is equal to the change in internal energy (U) of the system. Therefore,

    U = W = PΔV

    The change in internal energy is given by the equation:

    U = Q - W

    Where:
    U = change in internal energy
    Q = heat absorbed by the system
    W = work done by the system

    Since the water is freezing, the heat absorbed by the system (Q) is equal to the latent heat of ice (L). Therefore,

    U = L - PΔV

    Since the process is reversible, we can write:

    U = TΔS

    Where:
    T = temperature in Kelvin
    ΔS = change in entropy

    The change in entropy is given by the equation:

    ΔS = ΔQ / T

    Since the process is isothermal, ΔQ = Q = L. Therefore,

    ΔS = L / T

    Substituting the values of U and ΔS, we get:

    L / T = L - PΔV

    PΔV = L - L / T

    Simplifying the equation, we get:

    P = (L - L / T) / ΔV

    Substituting the given values, we get:

    P = (80 x 4.2 x 10^7 - 80 x 4.2 x 10^7 / T) / 0.091

    Step 4: Convert the temperature from Celsius to Kelvin
    Given temperature = -10°C
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    Community Answer
    Calculate the pressure (in atmospheres) required to make water freeze ...
    Given dT = 10C . V2 - V1 = -0.091 c.c.
    L = 80 cal. = 80 * 4.2 * 107 ergs, T = 0 + 273 = 273 K 
    Applying Clapeyrons latent heat equation

    or  dynes/cm2.

    = 135.2 Atmos.
    Hence to lower the melting of ice by 1°C, the pressure must be raised by 135.2 atmospheres.
    Now melting point of ice at atmospheric pressure is 0°C. Hence pressure required to make ice freeze at - 1 °C 
    = 135.2 + 1 = 136.2 atmospheres
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    Calculate the pressure (in atmospheres) required to make water freeze at - 10C. Change of specific volume when 1 gm of water freezes into ice = .091 cc.,J =4.2 x 107 ergs/cal..1 atmosphere 106 dynes / cm2 and the latent heat of ice = 80 cal./ gm.Correct answer is '136.2'. Can you explain this answer?
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    Calculate the pressure (in atmospheres) required to make water freeze at - 10C. Change of specific volume when 1 gm of water freezes into ice = .091 cc.,J =4.2 x 107 ergs/cal..1 atmosphere 106 dynes / cm2 and the latent heat of ice = 80 cal./ gm.Correct answer is '136.2'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Calculate the pressure (in atmospheres) required to make water freeze at - 10C. Change of specific volume when 1 gm of water freezes into ice = .091 cc.,J =4.2 x 107 ergs/cal..1 atmosphere 106 dynes / cm2 and the latent heat of ice = 80 cal./ gm.Correct answer is '136.2'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the pressure (in atmospheres) required to make water freeze at - 10C. Change of specific volume when 1 gm of water freezes into ice = .091 cc.,J =4.2 x 107 ergs/cal..1 atmosphere 106 dynes / cm2 and the latent heat of ice = 80 cal./ gm.Correct answer is '136.2'. Can you explain this answer?.
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