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Consider a conductor of resistance R length L and thickness D and resistivity r .Now this conductor is cut into four equal parts .What will be the new resistivity of each of these parts and why?
Most Upvoted Answer
Consider a conductor of resistance R length L and thickness D and resi...
Introduction:
When a conductor of resistance R, length L, thickness D, and resistivity r is cut into four equal parts, the resistivity of each part will change. To understand why this happens, we need to consider the factors that affect resistance and how they change when the conductor is divided.

Resistance and Resistivity:
Resistance (R) is a measure of how much a conductor opposes the flow of electric current. It depends on the resistivity (r) of the material, length (L) of the conductor, and its cross-sectional area (A). The relationship can be expressed using the formula R = (r * L) / A.

Changes in Length and Cross-sectional Area:
When the conductor is cut into four equal parts, both the length and cross-sectional area of each part change. Since the original conductor is divided into four equal parts, the length of each part will be L/4. The cross-sectional area of each part will also change since the original conductor's area is divided equally.

Changes in Resistivity:
The resistivity of a material is an intrinsic property that depends on the nature of the material itself. When the conductor is cut into four equal parts, the resistivity of each part remains the same as the original conductor.

Calculating New Resistance:
To calculate the new resistance of each part, we need to consider the changes in length and cross-sectional area. Since the length of each part is L/4 and the thickness remains the same, the new cross-sectional area will also be D. Using the formula mentioned earlier, we can calculate the new resistance of each part.

Conclusion:
When a conductor of resistance R, length L, thickness D, and resistivity r is cut into four equal parts, the resistivity of each part remains the same as the original conductor. However, the resistance of each part changes due to the changes in length and cross-sectional area. By considering these changes, we can calculate the new resistance using the formula R = (r * L/4) / D.
Community Answer
Consider a conductor of resistance R length L and thickness D and resi...
restivity of each part remain same
Explanation:
2'. 16R resistance cutted wire in parallel restaince will 4r in series 64R 3: series combination consume more because it has more resultant resistance
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Consider a conductor of resistance R length L and thickness D and resistivity r .Now this conductor is cut into four equal parts .What will be the new resistivity of each of these parts and why?
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Consider a conductor of resistance R length L and thickness D and resistivity r .Now this conductor is cut into four equal parts .What will be the new resistivity of each of these parts and why? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about Consider a conductor of resistance R length L and thickness D and resistivity r .Now this conductor is cut into four equal parts .What will be the new resistivity of each of these parts and why? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a conductor of resistance R length L and thickness D and resistivity r .Now this conductor is cut into four equal parts .What will be the new resistivity of each of these parts and why?.
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