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What was the day of the week on 16th August, 1947?
- a)Sunday
- b)Monday
- c)Saturday
- d)Thursday
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
What was the day of the week on 16thAugust, 1947?a)Sundayb)Mondayc)Sat...
15th August, 1947 = (1946 years + Period from 1st Jan., 1947 to 15th )
Counting of odd days:
1600 years have 0 odd day. 300 years have 1 odd day.
47 years = (11 leap years + 36 ordinary years)
= [(11 x 2) + (36 x 1) ] odd days
= 58 odd days
= 2 odd days
Jan Feb Mar Apr May Jun Jul Aug
= 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15
= 227 days
= (32 weeks + 3 days)
= 3,
Total number of odd days
= (0 + 1 + 2 + 3) odd days
= 6 odd days.
Hence, the required day was 'Saturday'.
Counting of odd days:
1600 years have 0 odd day. 300 years have 1 odd day.
47 years = (11 leap years + 36 ordinary years)
= [(11 x 2) + (36 x 1) ] odd days
= 58 odd days
= 2 odd days
Jan Feb Mar Apr May Jun Jul Aug
= 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15
= 227 days
= (32 weeks + 3 days)
= 3,
Total number of odd days
= (0 + 1 + 2 + 3) odd days
= 6 odd days.
Hence, the required day was 'Saturday'.
Most Upvoted Answer
What was the day of the week on 16thAugust, 1947?a)Sundayb)Mondayc)Sat...
Understanding the Day Calculation
To find the day of the week for any given date, we can use the Zeller's Congruence formula or a simpler method known as the "Doomsday rule." Here, we will use a straightforward approach to determine that August 16, 1947, was a Saturday.
Step-by-Step Calculation
1. Identify the Year and Month:
- Year: 1947
- Month: August
2. Determine the Anchor Day:
For the 20th century (1900-1999), the anchor day is Wednesday. Since 1947 is in the 20th century, we start from this reference.
3. Calculate the Year Code:
- Last two digits of the year: 47
- Divide by 12: 47 ÷ 12 = 3 (Quotient)
- Remainder: 47 - (3 * 12) = 11
- Year code: 3 (from quotient) + 11 (from remainder) = 14
- Now, take 14 modulo 7: 14 % 7 = 0 (Year code is 0)
4. Month Code for August:
- August has a month code of 3.
5. Calculate the Day Code:
- For the date: 16
- Total: Year code (0) + Month code (3) + Day (16) = 0 + 3 + 16 = 19
- Now, take 19 modulo 7: 19 % 7 = 5
6. Determine the Day of the Week:
- Starting from the anchor day (Wednesday), count 5 days forward:
- Wednesday (0), Thursday (1), Friday (2), Saturday (3), Sunday (4), Monday (5)
Therefore, August 16, 1947, was a Saturday.
Conclusion
The correct answer is indeed option 'C': Saturday.
To find the day of the week for any given date, we can use the Zeller's Congruence formula or a simpler method known as the "Doomsday rule." Here, we will use a straightforward approach to determine that August 16, 1947, was a Saturday.
Step-by-Step Calculation
1. Identify the Year and Month:
- Year: 1947
- Month: August
2. Determine the Anchor Day:
For the 20th century (1900-1999), the anchor day is Wednesday. Since 1947 is in the 20th century, we start from this reference.
3. Calculate the Year Code:
- Last two digits of the year: 47
- Divide by 12: 47 ÷ 12 = 3 (Quotient)
- Remainder: 47 - (3 * 12) = 11
- Year code: 3 (from quotient) + 11 (from remainder) = 14
- Now, take 14 modulo 7: 14 % 7 = 0 (Year code is 0)
4. Month Code for August:
- August has a month code of 3.
5. Calculate the Day Code:
- For the date: 16
- Total: Year code (0) + Month code (3) + Day (16) = 0 + 3 + 16 = 19
- Now, take 19 modulo 7: 19 % 7 = 5
6. Determine the Day of the Week:
- Starting from the anchor day (Wednesday), count 5 days forward:
- Wednesday (0), Thursday (1), Friday (2), Saturday (3), Sunday (4), Monday (5)
Therefore, August 16, 1947, was a Saturday.
Conclusion
The correct answer is indeed option 'C': Saturday.
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What was the day of the week on 16thAugust, 1947?a)Sundayb)Mondayc)Saturdayd)ThursdayCorrect answer is option 'C'. Can you explain this answer?
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