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January 1, 2004 was a Thursday, what day of the week lies on January 1 2005.
- a)Wednesday
- b)Thursday
- c)Friday
- d)Saturday
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
January 1, 2004 was a Thursday, what day of the week lies on January 1...
Given that January 1, 2004 was Thursday.
Odd days in 2004 = 2 (because 2004 is a leap year)
(Also note that we have taken the complete year 2004 because we need to find out the odd days from 01-Jan-2004 to 31-Dec-2004, that is the whole year 2004)
Hence January 1, 2005 = (Thursday + 2 odd days) = Saturday
Odd days in 2004 = 2 (because 2004 is a leap year)
(Also note that we have taken the complete year 2004 because we need to find out the odd days from 01-Jan-2004 to 31-Dec-2004, that is the whole year 2004)
Hence January 1, 2005 = (Thursday + 2 odd days) = Saturday
Most Upvoted Answer
January 1, 2004 was a Thursday, what day of the week lies on January 1...
Solution:
To find the day of the week on January 1, 2005, we need to count the number of days between January 1, 2004, and January 1, 2005, inclusive.
We know that a non-leap year has 365 days, so the number of days between January 1, 2004, and December 31, 2004, inclusive is 365 days.
Since January 1, 2005, is the next day after December 31, 2004, we add one day to the total number of days to get 366 days.
A leap year has 366 days, and the days of the week for the same date in consecutive years repeat after every 7 years. Therefore, the day of the week on January 1, 2005, will be the same as the day of the week on January 1, 1998.
January 1, 1998, was a Thursday, and since there are 7 days in a week, the day of the week on January 1, 2005, will be the same as the day of the week 7 years earlier, which is Saturday.
Therefore, the correct answer is option D) Saturday.
Summary:
- Number of days between January 1, 2004, and December 31, 2004, inclusive is 365 days.
- Adding one day to the total number of days gives 366 days.
- January 1, 2005, is a leap year with 366 days.
- The day of the week on January 1, 2005, will be the same as the day of the week on January 1, 1998.
- January 1, 1998, was a Thursday.
- The day of the week on January 1, 2005, will be the same as the day of the week 7 years earlier, which is Saturday.
- Therefore, the correct answer is option D) Saturday.
To find the day of the week on January 1, 2005, we need to count the number of days between January 1, 2004, and January 1, 2005, inclusive.
We know that a non-leap year has 365 days, so the number of days between January 1, 2004, and December 31, 2004, inclusive is 365 days.
Since January 1, 2005, is the next day after December 31, 2004, we add one day to the total number of days to get 366 days.
A leap year has 366 days, and the days of the week for the same date in consecutive years repeat after every 7 years. Therefore, the day of the week on January 1, 2005, will be the same as the day of the week on January 1, 1998.
January 1, 1998, was a Thursday, and since there are 7 days in a week, the day of the week on January 1, 2005, will be the same as the day of the week 7 years earlier, which is Saturday.
Therefore, the correct answer is option D) Saturday.
Summary:
- Number of days between January 1, 2004, and December 31, 2004, inclusive is 365 days.
- Adding one day to the total number of days gives 366 days.
- January 1, 2005, is a leap year with 366 days.
- The day of the week on January 1, 2005, will be the same as the day of the week on January 1, 1998.
- January 1, 1998, was a Thursday.
- The day of the week on January 1, 2005, will be the same as the day of the week 7 years earlier, which is Saturday.
- Therefore, the correct answer is option D) Saturday.
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January 1, 2004 was a Thursday, what day of the week lies on January 1 2005.a)Wednesdayb)Thursdayc)Fridayd)SaturdayCorrect answer is option 'D'. Can you explain this answer?
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