It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?a)Sundayb)Saturdayc)Fridayd)WednesdayCorrect answer is option 'C'. Can you explain this answer?

Question

Answer

The given question,'It was Sunday on Jan 1,2006.' for the word 'was' ,we have to count the odd days from the next year upto 2010...

2007- 1 odd day
2008- 2 odd days
2009- 1 odd day
2010 -1 odd day
total= 5 odd days
Sunday+5= Friday it will be.

Answer

Answer

Question:
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?

Answer:
To determine the day of the week on January 1, 2010, we need to consider the number of days between January 1, 2006, and January 1, 2010, and then calculate the remainder when dividing by 7.

Step 1: Calculate the number of days between the two dates:
To find the number of days between two dates, we can use the formula:
Number of days = (Number of years * 365) + Number of leap years + Number of days in the remaining year.

In this case:
Number of years = 2010 - 2006 = 4 years

To calculate the number of leap years, we need to consider the years divisible by 4 but not divisible by 100, unless divisible by 400. In this case, the years 2008 and 2012 are leap years.

Number of leap years = 2

The number of days in the remaining year can be calculated by counting the number of days from January 1, 2006, to December 31, 2006. In a non-leap year, there are 365 days.

Number of days in the remaining year = 365

Plugging these values into the formula, we get:
Number of days = (4 * 365) + 2 + 365 = 1462 days

Step 2: Calculate the remainder when dividing by 7:
Since there are 7 days in a week, we can divide the total number of days by 7 and find the remainder.

1462 % 7 = 0

Step 3: Determine the day of the week:
The remainder obtained (0) corresponds to Sunday. Therefore, January 1, 2010, was a Sunday.

Conclusion:
The day of the week on January 1, 2010, was Sunday.

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