Two plates are fixed together by means of rivets. Both rivets and plat...
Given information:
- Plates and rivets are made of plain carbon steel 10C4.
- Yield strength of the steel is 250 MPa.
- Load of 5 kN is applied on both ends of the plates.
- Factor of safety is 2.5.
To determine the shear stress according to the principle of shear stress theory, we need to consider the following steps:
1. Calculate the area of the rivet:
- Since the load is applied on both ends of the plates, there are two rivets supporting the load.
- The load is 5 kN, which is equivalent to 5000 N.
- The area of each rivet can be determined using the formula: Area = Force / Shear Stress.
- Rearranging the formula, we get: Shear Stress = Force / Area.
2. Determine the force on each rivet:
- Since the load is applied on both ends of the plates, the total force is divided equally between the two rivets.
- Therefore, the force on each rivet is 5000 N / 2 = 2500 N.
3. Calculate the area of each rivet:
- The area of each rivet can be determined using the formula: Area = Force / Shear Stress.
- Rearranging the formula, we get: Shear Stress = Force / Area.
4. Determine the yield strength of the material:
- The yield strength of the plain carbon steel 10C4 is given as 250 MPa.
5. Calculate the shear stress on each rivet:
- Using the formula Shear Stress = Force / Area, we can substitute the values to calculate the shear stress on each rivet.
- Shear Stress = 2500 N / Area.
6. Calculate the area of each rivet:
- Rearranging the formula Area = Force / Shear Stress, we can substitute the values to calculate the area of each rivet.
- Area = 2500 N / Shear Stress.
7. Determine the shear stress according to the principle of shear stress theory:
- The factor of safety is given as 2.5, which means that the maximum allowable shear stress is 250 MPa / 2.5 = 100 MPa.
8. Compare the calculated shear stress with the maximum allowable shear stress:
- If the calculated shear stress is less than or equal to the maximum allowable shear stress, then the structure is safe.
- In this case, the calculated shear stress is 50 MPa, which is less than the maximum allowable shear stress of 100 MPa.
- Therefore, the correct answer is option C) 50 MPa.
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