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A super heterodyne receiver is designed to receive transmitted signals between 5 and 10 MHz. High-side tuning is to be used. The tuning range of the local oscillator for IF frequency 500 kHz would be
  • a)
    4.5 MHz - 9.5 MHz
  • b)
    5.5 MHz - 10.5 MHz
  • c)
    4.5 MHz - 10.5 MHz
  • d)
    None of the above
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A super heterodyne receiver is designed to receive transmitted signals...
Since High-side tuning is used
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Most Upvoted Answer
A super heterodyne receiver is designed to receive transmitted signals...
Answer:
To understand the tuning range of the local oscillator (LO) in a super heterodyne receiver, we need to consider the frequency conversion process.

Frequency Conversion Process:
In a super heterodyne receiver, the received signal is mixed with the frequency of the local oscillator to convert it to an intermediate frequency (IF). The IF frequency is then amplified and demodulated to extract the original information signal.

Tuning Range:
The tuning range of the LO determines the range of frequencies that the receiver can tune into. In this case, the receiver is designed to receive signals between 5 and 10 MHz. High-side tuning means that the LO frequency is higher than the received frequency.

Calculating the LO Frequency Range:
To calculate the LO frequency range, we need to determine the minimum and maximum LO frequencies required to cover the desired frequency range.

Minimum LO Frequency:
The minimum LO frequency is obtained when the received frequency is at its maximum value (10 MHz). The LO frequency is given by:
LO_min = Received Frequency + IF Frequency
LO_min = 10 MHz + 500 kHz
LO_min = 10.5 MHz

Maximum LO Frequency:
The maximum LO frequency is obtained when the received frequency is at its minimum value (5 MHz). The LO frequency is given by:
LO_max = Received Frequency + IF Frequency
LO_max = 5 MHz + 500 kHz
LO_max = 5.5 MHz

Tuning Range:
The tuning range of the LO is the range between the minimum and maximum LO frequencies:
Tuning Range = LO_max - LO_min
Tuning Range = 5.5 MHz - 10.5 MHz
Tuning Range = 5 MHz

Conclusion:
The tuning range of the LO for an IF frequency of 500 kHz in a super heterodyne receiver designed to receive signals between 5 and 10 MHz is 5.5 MHz to 10.5 MHz. Therefore, the correct answer is option B, 5.5 MHz - 10.5 MHz.
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A super heterodyne receiver is designed to receive transmitted signals between 5 and 10 MHz. High-side tuning is to be used. The tuning range of the local oscillator for IF frequency 500 kHz would bea)4.5 MHz - 9.5 MHzb)5.5 MHz - 10.5 MHzc)4.5 MHz - 10.5 MHzd)None of the aboveCorrect answer is option 'B'. Can you explain this answer?
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A super heterodyne receiver is designed to receive transmitted signals between 5 and 10 MHz. High-side tuning is to be used. The tuning range of the local oscillator for IF frequency 500 kHz would bea)4.5 MHz - 9.5 MHzb)5.5 MHz - 10.5 MHzc)4.5 MHz - 10.5 MHzd)None of the aboveCorrect answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A super heterodyne receiver is designed to receive transmitted signals between 5 and 10 MHz. High-side tuning is to be used. The tuning range of the local oscillator for IF frequency 500 kHz would bea)4.5 MHz - 9.5 MHzb)5.5 MHz - 10.5 MHzc)4.5 MHz - 10.5 MHzd)None of the aboveCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A super heterodyne receiver is designed to receive transmitted signals between 5 and 10 MHz. High-side tuning is to be used. The tuning range of the local oscillator for IF frequency 500 kHz would bea)4.5 MHz - 9.5 MHzb)5.5 MHz - 10.5 MHzc)4.5 MHz - 10.5 MHzd)None of the aboveCorrect answer is option 'B'. Can you explain this answer?.
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