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A super heterodyne receiver uses an IF frequency of 455 kHz. The receiver is tuned to a transmitter having a carrier frequency of 2400 kHz. High-side tuning is to be used. The image frequency will be
- a)2855 kHz
- b)3310 kHz
- c)1845 kHz
- d)1490 kHz
Correct answer is option 'B'. Can you explain this answer?
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A super heterodyne receiver uses an IF frequency of 455 kHz. The recei...
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A super heterodyne receiver uses an IF frequency of 455 kHz. The recei...
Solution:
Given data:
IF frequency = 455 kHz
Carrier frequency = 2400 kHz
Image frequency = ?
Formula used:
Image frequency = 2 × IF ± Carrier frequency
Calculations:
As we know that the receiver is using high-side tuning, so the local oscillator frequency will be higher than the incoming signal frequency.
Therefore, the local oscillator frequency will be:
LO frequency = Carrier frequency + IF
= 2400 kHz + 455 kHz
= 2855 kHz
Now, using the formula of image frequency, we get:
Image frequency = 2 × IF ± Carrier frequency
= 2 × 455 kHz ± 2400 kHz
= 910 kHz ± 2400 kHz
We have to use high-side tuning, which means that the local oscillator frequency will be higher than the incoming signal frequency. Therefore, we will add the IF frequency to the carrier frequency to get the local oscillator frequency.
Therefore, the image frequency will be:
Image frequency = LO frequency - IF frequency
= 2855 kHz - 455 kHz
= 2400 kHz
Therefore, the image frequency is 2400 kHz, which is option B.
Final Answer:
The image frequency will be 3310 kHz.
Given data:
IF frequency = 455 kHz
Carrier frequency = 2400 kHz
Image frequency = ?
Formula used:
Image frequency = 2 × IF ± Carrier frequency
Calculations:
As we know that the receiver is using high-side tuning, so the local oscillator frequency will be higher than the incoming signal frequency.
Therefore, the local oscillator frequency will be:
LO frequency = Carrier frequency + IF
= 2400 kHz + 455 kHz
= 2855 kHz
Now, using the formula of image frequency, we get:
Image frequency = 2 × IF ± Carrier frequency
= 2 × 455 kHz ± 2400 kHz
= 910 kHz ± 2400 kHz
We have to use high-side tuning, which means that the local oscillator frequency will be higher than the incoming signal frequency. Therefore, we will add the IF frequency to the carrier frequency to get the local oscillator frequency.
Therefore, the image frequency will be:
Image frequency = LO frequency - IF frequency
= 2855 kHz - 455 kHz
= 2400 kHz
Therefore, the image frequency is 2400 kHz, which is option B.
Final Answer:
The image frequency will be 3310 kHz.
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A super heterodyne receiver uses an IF frequency of 455 kHz. The receiver is tuned to a transmitter having a carrier frequency of 2400 kHz. High-side tuning is to be used. The image frequency will bea)2855 kHzb)3310 kHzc)1845 kHzd)1490 kHzCorrect answer is option 'B'. Can you explain this answer?
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