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Consider a super heterodyne receiver tuned to 600 kHz. If the local oscillator feeds a 1000 kHz signal to the mixer, the image frequency (in integer) is _______ kHz.
Correct answer is '1400'. Can you explain this answer?
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Consider a super heterodyne receiver tuned to 600 kHz. If the local os...
Explanation:
Super Heterodyne Receiver: It is a radio frequency (RF) receiver that uses a frequency converter, known as a mixer, to produce an intermediate frequency (IF) from the incoming RF signal.
Local Oscillator: It is a signal generator that produces a signal with a frequency that is close to the desired frequency of the incoming signal.
Mixer: It is an electronic device that combines two signals to produce a new signal that is the sum and difference of the original frequencies.
When a radio frequency signal is received, it is mixed with a local oscillator signal in the mixer. The output of the mixer contains both the sum and difference frequencies of the two input signals. The difference frequency is the desired intermediate frequency (IF), which is then amplified and demodulated to extract the original information.
Image Frequency: It is an unwanted signal that can interfere with the desired signal in a receiver. It is a signal that is equal in frequency to the desired signal plus or minus twice the intermediate frequency.
Calculation:
Given, the receiver is tuned to 600 kHz and the local oscillator feeds a 1000 kHz signal to the mixer.
The intermediate frequency (IF) is the difference between the incoming signal and the local oscillator frequency, which is:
IF = 1000 kHz - 600 kHz = 400 kHz
The image frequency is equal to the sum or difference of the incoming signal and twice the intermediate frequency, which is:
Image frequency = 600 kHz + (2 × 400 kHz) = 1400 kHz
Therefore, the image frequency is 1400 kHz.
Super Heterodyne Receiver: It is a radio frequency (RF) receiver that uses a frequency converter, known as a mixer, to produce an intermediate frequency (IF) from the incoming RF signal.
Local Oscillator: It is a signal generator that produces a signal with a frequency that is close to the desired frequency of the incoming signal.
Mixer: It is an electronic device that combines two signals to produce a new signal that is the sum and difference of the original frequencies.
When a radio frequency signal is received, it is mixed with a local oscillator signal in the mixer. The output of the mixer contains both the sum and difference frequencies of the two input signals. The difference frequency is the desired intermediate frequency (IF), which is then amplified and demodulated to extract the original information.
Image Frequency: It is an unwanted signal that can interfere with the desired signal in a receiver. It is a signal that is equal in frequency to the desired signal plus or minus twice the intermediate frequency.
Calculation:
Given, the receiver is tuned to 600 kHz and the local oscillator feeds a 1000 kHz signal to the mixer.
The intermediate frequency (IF) is the difference between the incoming signal and the local oscillator frequency, which is:
IF = 1000 kHz - 600 kHz = 400 kHz
The image frequency is equal to the sum or difference of the incoming signal and twice the intermediate frequency, which is:
Image frequency = 600 kHz + (2 × 400 kHz) = 1400 kHz
Therefore, the image frequency is 1400 kHz.
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Consider a super heterodyne receiver tuned to 600 kHz. If the local os...
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Hence, the image frequency is 1400 kHz.
Question_Type: 4
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Consider a super heterodyne receiver tuned to 600 kHz. If the local oscillator feeds a 1000 kHz signal to the mixer, the image frequency (in integer) is _______ kHz.Correct answer is '1400'. Can you explain this answer?
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