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A ball is projected from the ground at an angle 60 degree from the ground if ball just clears a wall 5 m from the point of projection and falls on the ground 15 m away from it on other side then the height of the wall is nearly equal to ?
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A ball is projected from the ground at an angle 60 degree from the gro...
Problem Statement: A ball is projected from the ground at an angle 60 degree from the ground if ball just clears a wall 5 m from the point of projection and falls on the ground 15 m away from it on other side then the height of the wall is nearly equal to?
Solution:
Step 1: Draw a diagram
Step 2: Analyze the given data
- The angle of projection is 60 degrees from the ground.
- The ball just clears a wall located 5m from the point of projection.
- The ball lands on the ground 15m away from the wall.
Step 3: Calculate the initial velocity of the ball.
The horizontal distance traveled by the ball is 15m. The time taken to cover this distance can be calculated as follows:
15 = V₀cos(60)t
where V₀ is the initial velocity of the ball and t is the time taken.
Since the angle of projection is 60 degrees, the vertical component of velocity is V₀sin(60) and the time taken for the ball to reach maximum height can be calculated as follows:
0 = V₀sin(60)t - (1/2)gt²
where g is the acceleration due to gravity.
Solving the two equations simultaneously for V₀, we get:
V₀ = 20.41 m/s
Step 4: Calculate the time taken by the ball to clear the wall.
The horizontal distance traveled by the ball to clear the wall is 5m. The time taken to cover this distance can be calculated as follows:
5 = V₀cos(60)t
t = 0.72 s
Step 5: Calculate the height of the wall.
The maximum height reached by the ball can be calculated as follows:
H = V₀sin(60)t - (1/2)gt²
H = (20.41 m/s)(0.5)(0.72 s) - (1/2)(9.81 m/s²)(0.72 s)²
H = 5.13 m
Therefore, the height of the wall is approximately 5.13m.
Solution:
Step 1: Draw a diagram
Step 2: Analyze the given data
- The angle of projection is 60 degrees from the ground.
- The ball just clears a wall located 5m from the point of projection.
- The ball lands on the ground 15m away from the wall.
Step 3: Calculate the initial velocity of the ball.
The horizontal distance traveled by the ball is 15m. The time taken to cover this distance can be calculated as follows:
15 = V₀cos(60)t
where V₀ is the initial velocity of the ball and t is the time taken.
Since the angle of projection is 60 degrees, the vertical component of velocity is V₀sin(60) and the time taken for the ball to reach maximum height can be calculated as follows:
0 = V₀sin(60)t - (1/2)gt²
where g is the acceleration due to gravity.
Solving the two equations simultaneously for V₀, we get:
V₀ = 20.41 m/s
Step 4: Calculate the time taken by the ball to clear the wall.
The horizontal distance traveled by the ball to clear the wall is 5m. The time taken to cover this distance can be calculated as follows:
5 = V₀cos(60)t
t = 0.72 s
Step 5: Calculate the height of the wall.
The maximum height reached by the ball can be calculated as follows:
H = V₀sin(60)t - (1/2)gt²
H = (20.41 m/s)(0.5)(0.72 s) - (1/2)(9.81 m/s²)(0.72 s)²
H = 5.13 m
Therefore, the height of the wall is approximately 5.13m.
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A ball is projected from the ground at an angle 60 degree from the gro...
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A ball is projected from the ground at an angle 60 degree from the ground if ball just clears a wall 5 m from the point of projection and falls on the ground 15 m away from it on other side then the height of the wall is nearly equal to ?
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A ball is projected from the ground at an angle 60 degree from the ground if ball just clears a wall 5 m from the point of projection and falls on the ground 15 m away from it on other side then the height of the wall is nearly equal to ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ball is projected from the ground at an angle 60 degree from the ground if ball just clears a wall 5 m from the point of projection and falls on the ground 15 m away from it on other side then the height of the wall is nearly equal to ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball is projected from the ground at an angle 60 degree from the ground if ball just clears a wall 5 m from the point of projection and falls on the ground 15 m away from it on other side then the height of the wall is nearly equal to ?.
A ball is projected from the ground at an angle 60 degree from the ground if ball just clears a wall 5 m from the point of projection and falls on the ground 15 m away from it on other side then the height of the wall is nearly equal to ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ball is projected from the ground at an angle 60 degree from the ground if ball just clears a wall 5 m from the point of projection and falls on the ground 15 m away from it on other side then the height of the wall is nearly equal to ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball is projected from the ground at an angle 60 degree from the ground if ball just clears a wall 5 m from the point of projection and falls on the ground 15 m away from it on other side then the height of the wall is nearly equal to ?.
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