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There are 5 men and 3 women. In how many ways a committee of 3 members can be made such that 2 particular men are always to be excluded.
  • a)
    50
  • b)
    20
  • c)
    24
  • d)
    48
  • e)
    None of these
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
There are 5 men and 3 women. In how many ways a committee of 3 members...
B) 20
Explanation: Total 8 people, 2 men are to excluded, so 6 men left to be chosen from and 3 members to be chosen. So ways are 6C3 .
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Most Upvoted Answer
There are 5 men and 3 women. In how many ways a committee of 3 members...
Given: 5 men and 3 women, committee of 3 members to be formed, 2 particular men are to be excluded

To solve this problem, we need to find the number of ways to form a committee of 3 members from the remaining 3 men and 3 women.

Method:

- Total ways to form a committee of 3 members from 8 people = 8C3
- Ways to include the 2 particular men in the committee = 1 (as both are fixed)
- Remaining people = 3 men and 3 women
- Ways to select the remaining 1 member from the 3 men and 3 women = 3C1
- Total number of ways to form the committee excluding the 2 particular men = 8C3 - 1*3C1
- Solving this, we get 20 as the answer.

Therefore, the correct answer is option B) 20.
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Community Answer
There are 5 men and 3 women. In how many ways a committee of 3 members...
B) 20
Explanation: Total 8 people, 2 men are to excluded, so 6 men left to be chosen from and 3 members to be chosen. So ways are 6C3 .
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There are 5 men and 3 women. In how many ways a committee of 3 members can be made such that 2 particular men are always to be excluded.a)50b)20c)24d)48e)None of theseCorrect answer is option 'B'. Can you explain this answer?
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