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Weight of A and B are in the ratio of 3:5. If the weight of A is increased by 20 percent and then the total weight becomes 132 kg with an increase of 10 percent. B weight is increased by what percent.
  • a)
    2%
  • b)
    3%
  • c)
    4%
  • d)
    5%
  • e)
    None of these
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Weight of A and B are in the ratio of 3:5. If the weight of A is incre...
Answer – 3. 4% Explanation : Weight of A and B are 3x and 5x.
Initial weight before increase = (132*100)/110 = 120 8x = 120. X = 15 Initial weight of A and B are 45 and 75 kg respectively.
New weight of A = 54 so weight of B = 132 – 54 = 78.
So % increase = [(78-75)/75]*100 = 4 %
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Most Upvoted Answer
Weight of A and B are in the ratio of 3:5. If the weight of A is incre...
Answer – 3. 4% Explanation : Weight of A and B are 3x and 5x.
Initial weight before increase = (132*100)/110 = 120 8x = 120. X = 15 Initial weight of A and B are 45 and 75 kg respectively.
New weight of A = 54 so weight of B = 132 – 54 = 78.
So % increase = [(78-75)/75]*100 = 4 %
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Community Answer
Weight of A and B are in the ratio of 3:5. If the weight of A is incre...
Given:

The weight of A and B are in the ratio of 3:5.
Let the weight of A be 3x and B be 5x.

A's weight is increased by 20%, so the new weight of A becomes 1.2*3x = 3.6x.

The total weight is increased by 10%, so the new total weight becomes 1.1*(3.6x+5x) = 132 kg.

Solving for x, we get x = 10.

So, the weight of A is 3*10 = 30 kg and the weight of B is 5*10 = 50 kg.

Let B's weight be increased by y%.

Then, the new weight of B becomes (1+y/100)*50 = 50 + 0.5y.

We know that the new total weight is 132 kg.

So, 3.6x + (50 + 0.5y) = 132.

Solving for y, we get y = 4%.

Hence, B's weight is increased by 4%.

Answer: Option C (4%)
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