A vessel contains 1 mole of O2 gas (molar mass 32)... more at a temper...
From Charles law , P is proportional to T
P/T=P'/2T
P'=2P.
P'=final pressure.....
A vessel contains 1 mole of O2 gas (molar mass 32)... more at a temper...
Given:
- Vessel 1 contains 1 mole of O2 gas with a molar mass of 32 at temperature T.
- The pressure of the gas in vessel 1 is p.
- Vessel 2 contains 1 mole of the gas with a molar mass of 4 at temperature 2T.
To Find:
The pressure of the gas in vessel 2.
Solution:
1. Ideal Gas Law:
The ideal gas law relates the pressure, volume, temperature, and number of moles of a gas. It can be written as:
PV = nRT
Where:
P = pressure of the gas
V = volume of the gas
n = number of moles of the gas
R = ideal gas constant
T = temperature of the gas
2. Relationship between Pressure, Volume, and Temperature:
According to the ideal gas law, if the number of moles and volume of a gas are constant, then the pressure of the gas is directly proportional to its temperature. Mathematically, this can be expressed as:
P1/T1 = P2/T2
Where:
P1 = pressure of gas 1
T1 = temperature of gas 1
P2 = pressure of gas 2
T2 = temperature of gas 2
3. Applying the Relationship:
In this problem, the number of moles is the same in both vessels (1 mole). Therefore, we can apply the relationship between pressure and temperature to find the pressure of the gas in vessel 2.
We are given that the temperature of vessel 1 is T and the pressure is p. The temperature of vessel 2 is 2T. Let's substitute these values into the relationship:
P1/T1 = P2/T2
p/T = P2/(2T)
Simplifying the equation, we get:
p = P2/2
To find the pressure of the gas in vessel 2, we can rearrange the equation:
P2 = 2p
4. Answer:
Therefore, the pressure of the gas in vessel 2 is 2p. Option 'C' is the correct answer.