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The PC contains 0450 H and SP contains 08D 6 H. What will be content of P and SP following a CALL to subroutine at location 02 AFH?
- a)0453 H, 08 D 8 H
- b)0453 H, 08 D 4 H
- c)02 AFH, 08 D 8 H
- d)02 AFH, 08 D 4 H
Correct answer is option 'D'. Can you explain this answer?
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The PC contains 0450 H and SP contains 08D 6 H. What will be content o...
Content of the PC and SP registers following a CALL to subroutine at location 02 AFH can be determined by analyzing the instruction.
The CALL instruction is a type of branch instruction in a computer program that allows the program to jump to a subroutine and save the address of the next instruction in the stack. The address of the subroutine is specified in the instruction itself.
To determine the content of the PC and SP registers after the CALL instruction, we need to consider the current values of the PC and SP registers and the address specified in the CALL instruction.
Given:
PC = 0450 H
SP = 08D 6 H
We can break down the CALL instruction at location 02 AFH as follows:
- The opcode for the CALL instruction is 02.
- The address specified in the instruction is AFH.
To calculate the content of the PC register after the CALL instruction, we need to save the address of the next instruction in the stack and update the PC with the address specified in the CALL instruction.
- Save the address of the next instruction (PC + 1) in the stack:
- Push (PC + 1) onto the stack.
- SP ← SP - 2 (decrement SP by 2 to point to the top of the stack).
- Write (PC + 1) to the memory location pointed by SP.
- Update the PC with the address specified in the CALL instruction:
- PC ← AFH.
Calculating the content of the PC register:
- Save (PC + 1) = 0451 H in the memory location pointed by SP = 08D 6 H.
- Update PC with AFH = 02 AFH.
Therefore, the content of the PC register following the CALL instruction will be: 02 AFH.
To calculate the content of the SP register after the CALL instruction, we need to decrement the SP by 2 to point to the top of the stack.
Calculating the content of the SP register:
- SP ← SP - 2 = 08D 6 H - 2 = 08D 4 H.
Therefore, the content of the SP register following the CALL instruction will be: 08D 4 H.
Hence, the correct answer is option 'D': 02 AFH, 08 D 4 H.
The CALL instruction is a type of branch instruction in a computer program that allows the program to jump to a subroutine and save the address of the next instruction in the stack. The address of the subroutine is specified in the instruction itself.
To determine the content of the PC and SP registers after the CALL instruction, we need to consider the current values of the PC and SP registers and the address specified in the CALL instruction.
Given:
PC = 0450 H
SP = 08D 6 H
We can break down the CALL instruction at location 02 AFH as follows:
- The opcode for the CALL instruction is 02.
- The address specified in the instruction is AFH.
To calculate the content of the PC register after the CALL instruction, we need to save the address of the next instruction in the stack and update the PC with the address specified in the CALL instruction.
- Save the address of the next instruction (PC + 1) in the stack:
- Push (PC + 1) onto the stack.
- SP ← SP - 2 (decrement SP by 2 to point to the top of the stack).
- Write (PC + 1) to the memory location pointed by SP.
- Update the PC with the address specified in the CALL instruction:
- PC ← AFH.
Calculating the content of the PC register:
- Save (PC + 1) = 0451 H in the memory location pointed by SP = 08D 6 H.
- Update PC with AFH = 02 AFH.
Therefore, the content of the PC register following the CALL instruction will be: 02 AFH.
To calculate the content of the SP register after the CALL instruction, we need to decrement the SP by 2 to point to the top of the stack.
Calculating the content of the SP register:
- SP ← SP - 2 = 08D 6 H - 2 = 08D 4 H.
Therefore, the content of the SP register following the CALL instruction will be: 08D 4 H.
Hence, the correct answer is option 'D': 02 AFH, 08 D 4 H.
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The PC contains 0450 H and SP contains 08D 6 H. What will be content of P and SP following a CALL to subroutine at location 02 AFH?a)0453 H, 08 D 8 Hb)0453 H, 08 D 4 Hc)02 AFH, 08 D 8 Hd)02 AFH, 08 D 4 HCorrect answer is option 'D'. Can you explain this answer?
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The PC contains 0450 H and SP contains 08D 6 H. What will be content of P and SP following a CALL to subroutine at location 02 AFH?a)0453 H, 08 D 8 Hb)0453 H, 08 D 4 Hc)02 AFH, 08 D 8 Hd)02 AFH, 08 D 4 HCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The PC contains 0450 H and SP contains 08D 6 H. What will be content of P and SP following a CALL to subroutine at location 02 AFH?a)0453 H, 08 D 8 Hb)0453 H, 08 D 4 Hc)02 AFH, 08 D 8 Hd)02 AFH, 08 D 4 HCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The PC contains 0450 H and SP contains 08D 6 H. What will be content of P and SP following a CALL to subroutine at location 02 AFH?a)0453 H, 08 D 8 Hb)0453 H, 08 D 4 Hc)02 AFH, 08 D 8 Hd)02 AFH, 08 D 4 HCorrect answer is option 'D'. Can you explain this answer?.
The PC contains 0450 H and SP contains 08D 6 H. What will be content of P and SP following a CALL to subroutine at location 02 AFH?a)0453 H, 08 D 8 Hb)0453 H, 08 D 4 Hc)02 AFH, 08 D 8 Hd)02 AFH, 08 D 4 HCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The PC contains 0450 H and SP contains 08D 6 H. What will be content of P and SP following a CALL to subroutine at location 02 AFH?a)0453 H, 08 D 8 Hb)0453 H, 08 D 4 Hc)02 AFH, 08 D 8 Hd)02 AFH, 08 D 4 HCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The PC contains 0450 H and SP contains 08D 6 H. What will be content of P and SP following a CALL to subroutine at location 02 AFH?a)0453 H, 08 D 8 Hb)0453 H, 08 D 4 Hc)02 AFH, 08 D 8 Hd)02 AFH, 08 D 4 HCorrect answer is option 'D'. Can you explain this answer?.
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The PC contains 0450 H and SP contains 08D 6 H. What will be content of P and SP following a CALL to subroutine at location 02 AFH?a)0453 H, 08 D 8 Hb)0453 H, 08 D 4 Hc)02 AFH, 08 D 8 Hd)02 AFH, 08 D 4 HCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for The PC contains 0450 H and SP contains 08D 6 H. What will be content of P and SP following a CALL to subroutine at location 02 AFH?a)0453 H, 08 D 8 Hb)0453 H, 08 D 4 Hc)02 AFH, 08 D 8 Hd)02 AFH, 08 D 4 HCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of The PC contains 0450 H and SP contains 08D 6 H. What will be content of P and SP following a CALL to subroutine at location 02 AFH?a)0453 H, 08 D 8 Hb)0453 H, 08 D 4 Hc)02 AFH, 08 D 8 Hd)02 AFH, 08 D 4 HCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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