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A train travels at a certain average speed for a distance of 63 km and then travels a distance of 72 km at an average speed of 6 km/hr more than its original speed. If it takes 3 hours to complete the total journey, what is the original speed of the train in km/hr?
- a)24
- b)33
- c)42
- d)66
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A train travels at a certain average speed for a distance of 63 km and...
Let the original speed be ‘S’.
Total time taken = 3 hr => 63/S + 72/S+6 = 3 You can solve the question easily if you just do an option check. Otherwise the long way is to solve the equation completely. Save time.
As we have 63 in the numerator, we can assume that S may be a multiple of 7. The only option available is 4. So, let us try with that. 63/42 + 72/48 = 3/2 + 3/2 = 3
You have the answer.
Total time taken = 3 hr => 63/S + 72/S+6 = 3 You can solve the question easily if you just do an option check. Otherwise the long way is to solve the equation completely. Save time.
As we have 63 in the numerator, we can assume that S may be a multiple of 7. The only option available is 4. So, let us try with that. 63/42 + 72/48 = 3/2 + 3/2 = 3
You have the answer.
Most Upvoted Answer
A train travels at a certain average speed for a distance of 63 km and...
Given information:
- Distance of first part of journey = 63 km
- Distance of second part of journey = 72 km
- Total time taken for the journey = 3 hours
Let's assume:
- Original speed of the train = x km/hr
- Speed for the second part of the journey = x + 6 km/hr
Calculating time taken for each part of the journey:
- Time taken for first part = Distance/Speed = 63/x hours
- Time taken for second part = Distance/Speed = 72/(x+6) hours
Given total time taken for the journey is 3 hours:
63/x + 72/(x+6) = 3
63/x + 72/(x+6) = 3
Multiplying through by x(x+6) to clear the fractions:
63(x+6) + 72x = 3x(x+6)
63x + 378 + 72x = 3x^2 + 18x
3x^2 - 117x - 378 = 0
x^2 - 39x - 126 = 0
(x-42)(x+3) = 0
Calculating the original speed of the train:
The original speed cannot be negative, so x = 42 km/hr
Therefore, the original speed of the train is 42 km/hr. Hence, option c) 42 is the correct answer.
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A train travels at a certain average speed for a distance of 63 km and then travels a distance of 72 km at an average speed of 6 km/hr more than its original speed. If it takes 3 hours to complete the total journey, what is the original speed of the train in km/hr?a)24b)33c)42d)66Correct answer is option 'C'. Can you explain this answer?
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A train travels at a certain average speed for a distance of 63 km and then travels a distance of 72 km at an average speed of 6 km/hr more than its original speed. If it takes 3 hours to complete the total journey, what is the original speed of the train in km/hr?a)24b)33c)42d)66Correct answer is option 'C'. Can you explain this answer? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A train travels at a certain average speed for a distance of 63 km and then travels a distance of 72 km at an average speed of 6 km/hr more than its original speed. If it takes 3 hours to complete the total journey, what is the original speed of the train in km/hr?a)24b)33c)42d)66Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A train travels at a certain average speed for a distance of 63 km and then travels a distance of 72 km at an average speed of 6 km/hr more than its original speed. If it takes 3 hours to complete the total journey, what is the original speed of the train in km/hr?a)24b)33c)42d)66Correct answer is option 'C'. Can you explain this answer?.
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