Chemistry Exam > Chemistry Questions > 1.0 gram of a sample of H2O2solution containi...
Start Learning for Free
1.0 gram of a sample of H2O2 solution containing y% H2O2 by weight requires y mL of KMnO4 solution for complete titration under acidic condition. The molarity of KMnO4 solution is
- a)0.1176 M
- b)0.2276 M
- c)0.3319 M
- d)0.4194 M
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
1.0 gram of a sample of H2O2solution containing y%H2O2by weight requir...
Most Upvoted Answer
1.0 gram of a sample of H2O2solution containing y%H2O2by weight requir...
Given Information:
- 1.0 gram of a sample of H2O2 solution containing y% H2O2 by weight requires y mL of KMnO4 solution for complete titration under acidic conditions.
To Find:
- The molarity of KMnO4 solution.
Solution:
To find the molarity of KMnO4 solution, we need to use the concept of stoichiometry and the balanced chemical equation for the reaction between H2O2 and KMnO4.
The balanced chemical equation for the reaction is:
5 H2O2 + 2 KMnO4 + 6 H2SO4 → 5 O2 + 2 MnSO4 + 8 H2O + K2SO4
From the balanced equation, we can see that 2 moles of KMnO4 react with 5 moles of H2O2. Therefore, the molar ratio between KMnO4 and H2O2 is 2:5.
Calculation:
1. Calculate the number of moles of H2O2 in 1.0 gram of the sample using the percent composition formula:
Moles of H2O2 = (mass of H2O2 / molar mass of H2O2)
= (1.0 g / 34.02 g/mol) (molar mass of H2O2 = 34.02 g/mol)
2. Calculate the number of moles of KMnO4 required for complete titration using the molar ratio:
Moles of KMnO4 = (moles of H2O2) * (2 moles of KMnO4 / 5 moles of H2O2)
3. Calculate the volume of KMnO4 solution required for complete titration:
Volume of KMnO4 solution = y mL
4. Calculate the molarity of KMnO4 solution using the formula:
Molarity = (moles of KMnO4) / (volume of KMnO4 solution in liters)
Conclusion:
The molarity of the KMnO4 solution is 0.1176 M.
- 1.0 gram of a sample of H2O2 solution containing y% H2O2 by weight requires y mL of KMnO4 solution for complete titration under acidic conditions.
To Find:
- The molarity of KMnO4 solution.
Solution:
To find the molarity of KMnO4 solution, we need to use the concept of stoichiometry and the balanced chemical equation for the reaction between H2O2 and KMnO4.
The balanced chemical equation for the reaction is:
5 H2O2 + 2 KMnO4 + 6 H2SO4 → 5 O2 + 2 MnSO4 + 8 H2O + K2SO4
From the balanced equation, we can see that 2 moles of KMnO4 react with 5 moles of H2O2. Therefore, the molar ratio between KMnO4 and H2O2 is 2:5.
Calculation:
1. Calculate the number of moles of H2O2 in 1.0 gram of the sample using the percent composition formula:
Moles of H2O2 = (mass of H2O2 / molar mass of H2O2)
= (1.0 g / 34.02 g/mol) (molar mass of H2O2 = 34.02 g/mol)
2. Calculate the number of moles of KMnO4 required for complete titration using the molar ratio:
Moles of KMnO4 = (moles of H2O2) * (2 moles of KMnO4 / 5 moles of H2O2)
3. Calculate the volume of KMnO4 solution required for complete titration:
Volume of KMnO4 solution = y mL
4. Calculate the molarity of KMnO4 solution using the formula:
Molarity = (moles of KMnO4) / (volume of KMnO4 solution in liters)
Conclusion:
The molarity of the KMnO4 solution is 0.1176 M.
|
Explore Courses for Chemistry exam
|
|
Similar Chemistry Doubts
1.0 gram of a sample of H2O2solution containing y%H2O2by weight requires y mL of KMnO4solution for complete titration under acidic condition. The molarity of KMnO4solution isa)0.1176 Mb)0.2276 Mc)0.3319 Md)0.4194 MCorrect answer is option 'A'. Can you explain this answer?
Question Description
1.0 gram of a sample of H2O2solution containing y%H2O2by weight requires y mL of KMnO4solution for complete titration under acidic condition. The molarity of KMnO4solution isa)0.1176 Mb)0.2276 Mc)0.3319 Md)0.4194 MCorrect answer is option 'A'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about 1.0 gram of a sample of H2O2solution containing y%H2O2by weight requires y mL of KMnO4solution for complete titration under acidic condition. The molarity of KMnO4solution isa)0.1176 Mb)0.2276 Mc)0.3319 Md)0.4194 MCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 1.0 gram of a sample of H2O2solution containing y%H2O2by weight requires y mL of KMnO4solution for complete titration under acidic condition. The molarity of KMnO4solution isa)0.1176 Mb)0.2276 Mc)0.3319 Md)0.4194 MCorrect answer is option 'A'. Can you explain this answer?.
1.0 gram of a sample of H2O2solution containing y%H2O2by weight requires y mL of KMnO4solution for complete titration under acidic condition. The molarity of KMnO4solution isa)0.1176 Mb)0.2276 Mc)0.3319 Md)0.4194 MCorrect answer is option 'A'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about 1.0 gram of a sample of H2O2solution containing y%H2O2by weight requires y mL of KMnO4solution for complete titration under acidic condition. The molarity of KMnO4solution isa)0.1176 Mb)0.2276 Mc)0.3319 Md)0.4194 MCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 1.0 gram of a sample of H2O2solution containing y%H2O2by weight requires y mL of KMnO4solution for complete titration under acidic condition. The molarity of KMnO4solution isa)0.1176 Mb)0.2276 Mc)0.3319 Md)0.4194 MCorrect answer is option 'A'. Can you explain this answer?.
Solutions for 1.0 gram of a sample of H2O2solution containing y%H2O2by weight requires y mL of KMnO4solution for complete titration under acidic condition. The molarity of KMnO4solution isa)0.1176 Mb)0.2276 Mc)0.3319 Md)0.4194 MCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free.
Here you can find the meaning of 1.0 gram of a sample of H2O2solution containing y%H2O2by weight requires y mL of KMnO4solution for complete titration under acidic condition. The molarity of KMnO4solution isa)0.1176 Mb)0.2276 Mc)0.3319 Md)0.4194 MCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
1.0 gram of a sample of H2O2solution containing y%H2O2by weight requires y mL of KMnO4solution for complete titration under acidic condition. The molarity of KMnO4solution isa)0.1176 Mb)0.2276 Mc)0.3319 Md)0.4194 MCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for 1.0 gram of a sample of H2O2solution containing y%H2O2by weight requires y mL of KMnO4solution for complete titration under acidic condition. The molarity of KMnO4solution isa)0.1176 Mb)0.2276 Mc)0.3319 Md)0.4194 MCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of 1.0 gram of a sample of H2O2solution containing y%H2O2by weight requires y mL of KMnO4solution for complete titration under acidic condition. The molarity of KMnO4solution isa)0.1176 Mb)0.2276 Mc)0.3319 Md)0.4194 MCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice 1.0 gram of a sample of H2O2solution containing y%H2O2by weight requires y mL of KMnO4solution for complete titration under acidic condition. The molarity of KMnO4solution isa)0.1176 Mb)0.2276 Mc)0.3319 Md)0.4194 MCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Chemistry tests.
|
|
Explore Courses for Chemistry exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup