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Acetic acid content in commercial vinegar was analyzed by titrating against 1.5 M NaOH solution. A 20 mL vinegar sample required 18 mL of titrant to give endpoint. The concentration of acetic acid in the vinegar (in mol L–1) is __.
Correct answer is between '1.3,1.4'. Can you explain this answer?
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Acetic acid content in commercial vinegar was analyzed by titrating ag...
Analysis of Acetic Acid Content in Commercial Vinegar
To determine the concentration of acetic acid in commercial vinegar, a titration method using a 1.5 M NaOH solution is employed. The titration involves the reaction between acetic acid and sodium hydroxide, resulting in the formation of sodium acetate and water.
The balanced chemical equation for the reaction is as follows:
CH3COOH + NaOH → CH3COONa + H2O
Given Information:
- Volume of vinegar sample = 20 mL
- Volume of titrant (1.5 M NaOH) required to reach the endpoint = 18 mL
Calculating the Number of Moles of NaOH:
To determine the concentration of acetic acid, we first need to calculate the number of moles of NaOH used in the titration.
Moles of NaOH = Molarity of NaOH × Volume of NaOH
Moles of NaOH = 1.5 mol/L × 0.018 L
Moles of NaOH = 0.027 mol
Calculating the Number of Moles of Acetic Acid:
Since the balanced chemical equation shows a 1:1 stoichiometric ratio between acetic acid and NaOH, the number of moles of acetic acid is equal to the number of moles of NaOH.
Moles of Acetic Acid = 0.027 mol
Calculating the Concentration of Acetic Acid:
To determine the concentration of acetic acid in the vinegar sample, we need to divide the number of moles of acetic acid by the volume of the vinegar sample.
Concentration of Acetic Acid = Moles of Acetic Acid / Volume of Vinegar Sample
Concentration of Acetic Acid = 0.027 mol / 0.020 L
Concentration of Acetic Acid = 1.35 mol/L
Conclusion:
Therefore, the concentration of acetic acid in the commercial vinegar sample is approximately 1.35 M. Since the given answer range is between 1.3 and 1.4 M, the calculated concentration falls within the specified range.
To determine the concentration of acetic acid in commercial vinegar, a titration method using a 1.5 M NaOH solution is employed. The titration involves the reaction between acetic acid and sodium hydroxide, resulting in the formation of sodium acetate and water.
The balanced chemical equation for the reaction is as follows:
CH3COOH + NaOH → CH3COONa + H2O
Given Information:
- Volume of vinegar sample = 20 mL
- Volume of titrant (1.5 M NaOH) required to reach the endpoint = 18 mL
Calculating the Number of Moles of NaOH:
To determine the concentration of acetic acid, we first need to calculate the number of moles of NaOH used in the titration.
Moles of NaOH = Molarity of NaOH × Volume of NaOH
Moles of NaOH = 1.5 mol/L × 0.018 L
Moles of NaOH = 0.027 mol
Calculating the Number of Moles of Acetic Acid:
Since the balanced chemical equation shows a 1:1 stoichiometric ratio between acetic acid and NaOH, the number of moles of acetic acid is equal to the number of moles of NaOH.
Moles of Acetic Acid = 0.027 mol
Calculating the Concentration of Acetic Acid:
To determine the concentration of acetic acid in the vinegar sample, we need to divide the number of moles of acetic acid by the volume of the vinegar sample.
Concentration of Acetic Acid = Moles of Acetic Acid / Volume of Vinegar Sample
Concentration of Acetic Acid = 0.027 mol / 0.020 L
Concentration of Acetic Acid = 1.35 mol/L
Conclusion:
Therefore, the concentration of acetic acid in the commercial vinegar sample is approximately 1.35 M. Since the given answer range is between 1.3 and 1.4 M, the calculated concentration falls within the specified range.
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Acetic acid content in commercial vinegar was analyzed by titrating ag...
In endpoint acetic acid is completely neutralised by NaOH.By putting the formula N1V1=N2V2 the concentration of acetic acid is 1.35 mol/L
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Acetic acid content in commercial vinegar was analyzed by titrating against 1.5 M NaOH solution. A 20 mL vinegar sample required 18 mL of titrant to give endpoint. The concentration of acetic acid in the vinegar (in mol L–1) is __.Correct answer is between '1.3,1.4'. Can you explain this answer?
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Acetic acid content in commercial vinegar was analyzed by titrating against 1.5 M NaOH solution. A 20 mL vinegar sample required 18 mL of titrant to give endpoint. The concentration of acetic acid in the vinegar (in mol L–1) is __.Correct answer is between '1.3,1.4'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Acetic acid content in commercial vinegar was analyzed by titrating against 1.5 M NaOH solution. A 20 mL vinegar sample required 18 mL of titrant to give endpoint. The concentration of acetic acid in the vinegar (in mol L–1) is __.Correct answer is between '1.3,1.4'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Acetic acid content in commercial vinegar was analyzed by titrating against 1.5 M NaOH solution. A 20 mL vinegar sample required 18 mL of titrant to give endpoint. The concentration of acetic acid in the vinegar (in mol L–1) is __.Correct answer is between '1.3,1.4'. Can you explain this answer?.
Acetic acid content in commercial vinegar was analyzed by titrating against 1.5 M NaOH solution. A 20 mL vinegar sample required 18 mL of titrant to give endpoint. The concentration of acetic acid in the vinegar (in mol L–1) is __.Correct answer is between '1.3,1.4'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Acetic acid content in commercial vinegar was analyzed by titrating against 1.5 M NaOH solution. A 20 mL vinegar sample required 18 mL of titrant to give endpoint. The concentration of acetic acid in the vinegar (in mol L–1) is __.Correct answer is between '1.3,1.4'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Acetic acid content in commercial vinegar was analyzed by titrating against 1.5 M NaOH solution. A 20 mL vinegar sample required 18 mL of titrant to give endpoint. The concentration of acetic acid in the vinegar (in mol L–1) is __.Correct answer is between '1.3,1.4'. Can you explain this answer?.
Solutions for Acetic acid content in commercial vinegar was analyzed by titrating against 1.5 M NaOH solution. A 20 mL vinegar sample required 18 mL of titrant to give endpoint. The concentration of acetic acid in the vinegar (in mol L–1) is __.Correct answer is between '1.3,1.4'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
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Acetic acid content in commercial vinegar was analyzed by titrating against 1.5 M NaOH solution. A 20 mL vinegar sample required 18 mL of titrant to give endpoint. The concentration of acetic acid in the vinegar (in mol L–1) is __.Correct answer is between '1.3,1.4'. Can you explain this answer?, a detailed solution for Acetic acid content in commercial vinegar was analyzed by titrating against 1.5 M NaOH solution. A 20 mL vinegar sample required 18 mL of titrant to give endpoint. The concentration of acetic acid in the vinegar (in mol L–1) is __.Correct answer is between '1.3,1.4'. Can you explain this answer? has been provided alongside types of Acetic acid content in commercial vinegar was analyzed by titrating against 1.5 M NaOH solution. A 20 mL vinegar sample required 18 mL of titrant to give endpoint. The concentration of acetic acid in the vinegar (in mol L–1) is __.Correct answer is between '1.3,1.4'. Can you explain this answer? theory, EduRev gives you an
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