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A stone is dropped from a height of 10 cm above the top of a window 80 cm high . The time taken by the stone to cross the window is?
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A stone is dropped from a height of 10 cm above the top of a window 80...
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A stone is dropped from a height of 10 cm above the top of a window 80...
Given:
- Height of the stone above the top of the window = 10 cm
- Height of the window = 80 cm

To find:
- Time taken by the stone to cross the window

Assumptions:
- The stone is dropped vertically, without any horizontal velocity.
- The only force acting on the stone is gravity.
- Air resistance is negligible.

Solution:
Let's break down the problem into two parts: the time taken by the stone to reach the top of the window and the time taken by the stone to fall from the top to the bottom of the window.

1. Time taken to reach the top of the window:
- The stone is dropped from a height of 10 cm above the top of the window.
- The initial velocity of the stone is zero since it is dropped vertically.
- The acceleration due to gravity is acting downward, which is approximately 9.8 m/s^2.
- We can use the equation of motion: h = ut + (1/2)gt^2, where h is the height, u is the initial velocity, g is the acceleration due to gravity, and t is the time taken.
- Plugging in the values, we have: 80 cm = 0 + (1/2)(9.8 m/s^2)t^2
- Converting the height to meters, we get: 0.8 m = (1/2)(9.8 m/s^2)t^2
- Simplifying the equation, we have: 0.8 m = 4.9 m/s^2 t^2
- Solving for t, we find t = √(0.8 m / 4.9 m/s^2) = 0.4 s

2. Time taken to fall from the top to the bottom of the window:
- Once the stone reaches the top of the window, it will start falling freely under the influence of gravity.
- The height of the window is 80 cm, which is equivalent to 0.8 m.
- Using the equation h = ut + (1/2)gt^2, where h is the height, u is the initial velocity, g is the acceleration due to gravity, and t is the time taken.
- Plugging in the values, we have: 0.8 m = 0 + (1/2)(9.8 m/s^2)t^2
- Simplifying the equation, we have: 0.8 m = 4.9 m/s^2 t^2
- Solving for t, we find t = √(0.8 m / 4.9 m/s^2) = 0.4 s

Conclusion:
- The total time taken by the stone to cross the window is the sum of the time taken to reach the top and the time taken to fall from the top to the bottom.
- Therefore, the total time taken by the stone to cross the window is 0.4 s + 0.4 s = 0.8 s.
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A stone is dropped from a height of 10 cm above the top of a window 80 cm high . The time taken by the stone to cross the window is?
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A stone is dropped from a height of 10 cm above the top of a window 80 cm high . The time taken by the stone to cross the window is? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A stone is dropped from a height of 10 cm above the top of a window 80 cm high . The time taken by the stone to cross the window is? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stone is dropped from a height of 10 cm above the top of a window 80 cm high . The time taken by the stone to cross the window is?.
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