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The concentration of a MgSO4 solution having the same ionic strength as that of a 0.1M Na2SO4 solution is ____(Round off to three decimal places)
Correct answer is '0.075'. Can you explain this answer?
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The concentration of a MgSO4 solution having the same ionic strength a...
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Explanation:
Ionic strength is the measure of the concentration of ions in a solution. It is given by the formula:
Ionic Strength (I) = 1/2 ∑ ci zi^2
Where, ci is the molar concentration of the ith ion and zi is the charge on the ion.
In this question, we need to find the concentration of a MgSO4 solution that has the same ionic strength as that of a 0.1 M Na2SO4 solution.
Step 1: Calculate the ionic strength of 0.1 M Na2SO4 solution.
Na2SO4 dissociates as follows:
Na2SO4 → 2Na+ + SO42-
The molar concentration of Na+ is 2 x 0.1 M = 0.2 M
The molar concentration of SO42- is 0.1 M
The charge on Na+ is +1 and that on SO42- is -2
Using the formula for ionic strength:
I = 1/2 [(0.2 x 1^2) + (0.1 x (-2)^2)]
I = 0.3
Step 2: Calculate the concentration of MgSO4 solution that has the same ionic strength as that of a 0.1 M Na2SO4 solution.
MgSO4 dissociates as follows:
MgSO4 → Mg2+ + SO42-
Let the concentration of MgSO4 solution be x M.
The molar concentration of Mg2+ is x M
The molar concentration of SO42- is x M
The charge on Mg2+ is +2 and that on SO42- is -2
Using the formula for ionic strength:
I = 1/2 [(x x 2^2) + (x x (-2)^2)]
0.3 = 1/2 [4x + 4x]
0.3 = 4x
x = 0.075 M
Therefore, the concentration of a MgSO4 solution having the same ionic strength as that of a 0.1 M Na2SO4 solution is 0.075 M.
Ionic strength is the measure of the concentration of ions in a solution. It is given by the formula:
Ionic Strength (I) = 1/2 ∑ ci zi^2
Where, ci is the molar concentration of the ith ion and zi is the charge on the ion.
In this question, we need to find the concentration of a MgSO4 solution that has the same ionic strength as that of a 0.1 M Na2SO4 solution.
Step 1: Calculate the ionic strength of 0.1 M Na2SO4 solution.
Na2SO4 dissociates as follows:
Na2SO4 → 2Na+ + SO42-
The molar concentration of Na+ is 2 x 0.1 M = 0.2 M
The molar concentration of SO42- is 0.1 M
The charge on Na+ is +1 and that on SO42- is -2
Using the formula for ionic strength:
I = 1/2 [(0.2 x 1^2) + (0.1 x (-2)^2)]
I = 0.3
Step 2: Calculate the concentration of MgSO4 solution that has the same ionic strength as that of a 0.1 M Na2SO4 solution.
MgSO4 dissociates as follows:
MgSO4 → Mg2+ + SO42-
Let the concentration of MgSO4 solution be x M.
The molar concentration of Mg2+ is x M
The molar concentration of SO42- is x M
The charge on Mg2+ is +2 and that on SO42- is -2
Using the formula for ionic strength:
I = 1/2 [(x x 2^2) + (x x (-2)^2)]
0.3 = 1/2 [4x + 4x]
0.3 = 4x
x = 0.075 M
Therefore, the concentration of a MgSO4 solution having the same ionic strength as that of a 0.1 M Na2SO4 solution is 0.075 M.
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The concentration of a MgSO4 solution having the same ionic strength as that of a 0.1M Na2SO4 solution is ____(Round off to three decimal places)Correct answer is '0.075'. Can you explain this answer?
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