Section A and section B of 7th class in a school contains total 285 st...
B) 10 : 9
Explanation: The number of boys and girls cannot be in decimal values, so the denominator should completely divide number of students (285).
Check each option: 6+5 = 11, and 11 does not divide 285 completely. 10+9 = 19, and only 19 divides 285 completely among all.
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Section A and section B of 7th class in a school contains total 285 st...
Given, total number of students in sections A and B of 7th class in a school is 285.
Let the ratio of number of boys to number of girls be x : y in section A and section B.
Then, we have the following equations:
- Number of boys in section A = x/(x+y) * total number of students in section A
- Number of girls in section A = y/(x+y) * total number of students in section A
- Number of boys in section B = x/(x+y) * total number of students in section B
- Number of girls in section B = y/(x+y) * total number of students in section B
We know that total number of students in sections A and B is 285. Therefore, we have:
- total number of students in section A = (285/2) = 142.5 (which is not possible as it is a decimal)
- total number of students in section B = (285/2) = 142.5 (which is not possible as it is a decimal)
Hence, we cannot determine the ratio of number of boys to number of girls in the class.
However, if we assume that the number of students in each section is a whole number, then we can proceed further.
Let the total number of students in section A be a and in section B be b. Then, we have:
- a + b = 285
- Number of boys in section A + Number of boys in section B = x/(x+y) * (a+b)
- Number of girls in section A + Number of girls in section B = y/(x+y) * (a+b)
Since we cannot determine a and b uniquely, we cannot determine x/y uniquely.
But, we can check which option satisfies the given condition.
- For option B, the ratio of boys to girls is 10:9. This can be written as 10x : 9x, which simplifies to x : (9/10)x. Therefore, the ratio of number of boys to number of girls can be 10 : 9.
Section A and section B of 7th class in a school contains total 285 st...
B) 10 : 9
Explanation: The number of boys and girls cannot be in decimal values, so the denominator should completely divide number of students (285).
Check each option: 6+5 = 11, and 11 does not divide 285 completely. 10+9 = 19, and only 19 divides 285 completely among all.