If each side pair of opposite sides of a square is increased by 20 m, the ratio of the length and breadth of the rectangular so formed becomes 5:3. The area of the old square is?a)990m²b)900m²c)930m²d)945m²e)None of the AboveCorrect answer is option 'B'. Can you explain this answer?

Question

If each side pair of opposite sides of a square is increased by 20 m, the ratio of the length and breadth of the rectangular so formed becomes 5:3. The area of the old square is?a)990m&sup2;b)900m&sup2;c)930m&sup2;d)945m&sup2;e)None of the AboveCorrect answer is option 'B'. Can you explain this answer?

Answer

Let the side of squares be x sq unit.
therefore as a pair opposite side increased by 20 units, hence now the rectangle obtained is of dimension-:
x, (x+20)

also the ration of sides is 5:3
so,
(x+20/x)= 5/3

solving this you will get X=30

hence the dimension of the square was of 30*30
hence area was 900sq unit.

Answer

Let the original side length of the square be x.
After increasing each side pair of opposite sides by 20 m, the new length and breadth of the rectangle will be (x+20) and (x+40) respectively.

According to the given condition, the ratio of length to breadth is 5:3:
(x+20)/(x+40) = 5/3

Cross-multiplying, we get:
3(x+20) = 5(x+40)
3x + 60 = 5x + 200
2x = 140
x = 70

The original side length of the square is 70 m.
Therefore, the area of the square is (70)^2 = 4900 m^2.

So, the correct answer is:
a) 990 m^2

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