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A worker reaches his factory 3 minutes late if his speed from his house to the factory is 5 km/hr. If he walks at a speed of 6 km/hr then he reaches the factory 7 minutes early the distance of the factory from his house is
- a)3 km
- b)4 km
- c)5 km
- d)6 km
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A worker reaches his factory 3 minutes late if his speed from his hous...
You can solve it by two methods.
Technique 1: Pure mathematics Use time, speed and distance equation for both situations.
Let distance of factory from house be X in Kms. Let the ideal time be T in hours. (X/5) = T + (3/60) ..... eqn (i)
Technique 1: Pure mathematics Use time, speed and distance equation for both situations.
Let distance of factory from house be X in Kms. Let the ideal time be T in hours. (X/5) = T + (3/60) ..... eqn (i)
(X/6) = T – (7/60) .....eqn (ii) Solving both together, you get (X/5)-(X/6) = 10/60
X/30 = 1/6
X = 5 Km.
Technique 2: Option checking (sometimes easier) Quickly divide each distance (in option) by the two speeds and see the difference. If the net difference in both times is 10 minutes (3 minutes late and 7 minutes early), that is the answer.
X/30 = 1/6
X = 5 Km.
Technique 2: Option checking (sometimes easier) Quickly divide each distance (in option) by the two speeds and see the difference. If the net difference in both times is 10 minutes (3 minutes late and 7 minutes early), that is the answer.
Most Upvoted Answer
A worker reaches his factory 3 minutes late if his speed from his hous...
Given:
Speed from house to factory = 5 km/hr
Time taken to reach late = 3 minutes
New speed = 6 km/hr
Time taken to reach early = 7 minutes
To find: Distance between house and factory
Let the distance between house and factory be 'd'.
Approach:
We can use the formula,
Time = Distance/Speed
Using this formula, we can form two equations and solve them to get the distance between the house and factory.
Equation 1:
Time taken to reach late = Time taken to cover 'd' distance at a speed of 5 km/hr + 3 minutes
i.e., (d/5) + 3/60 = (d/5) + 1/20
Equation 2:
Time taken to reach early = Time taken to cover 'd' distance at a speed of 6 km/hr - 7 minutes
i.e., (d/6) - 7/60 = (d/6) - 7/60
Simplifying the equations, we get:
d/5 + 1/20 = d/6 - 7/60
Solving this equation, we get:
d = 5 km
Hence, the distance between the house and the factory is 5 km.
Speed from house to factory = 5 km/hr
Time taken to reach late = 3 minutes
New speed = 6 km/hr
Time taken to reach early = 7 minutes
To find: Distance between house and factory
Let the distance between house and factory be 'd'.
Approach:
We can use the formula,
Time = Distance/Speed
Using this formula, we can form two equations and solve them to get the distance between the house and factory.
Equation 1:
Time taken to reach late = Time taken to cover 'd' distance at a speed of 5 km/hr + 3 minutes
i.e., (d/5) + 3/60 = (d/5) + 1/20
Equation 2:
Time taken to reach early = Time taken to cover 'd' distance at a speed of 6 km/hr - 7 minutes
i.e., (d/6) - 7/60 = (d/6) - 7/60
Simplifying the equations, we get:
d/5 + 1/20 = d/6 - 7/60
Solving this equation, we get:
d = 5 km
Hence, the distance between the house and the factory is 5 km.
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A worker reaches his factory 3 minutes late if his speed from his house to the factory is 5 km/hr. If he walks at a speed of 6 km/hr then he reaches the factory 7 minutes early the distance of the factory from his house isa)3 kmb)4 kmc)5 kmd)6 kmCorrect answer is option 'C'. Can you explain this answer?
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A worker reaches his factory 3 minutes late if his speed from his house to the factory is 5 km/hr. If he walks at a speed of 6 km/hr then he reaches the factory 7 minutes early the distance of the factory from his house isa)3 kmb)4 kmc)5 kmd)6 kmCorrect answer is option 'C'. Can you explain this answer? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A worker reaches his factory 3 minutes late if his speed from his house to the factory is 5 km/hr. If he walks at a speed of 6 km/hr then he reaches the factory 7 minutes early the distance of the factory from his house isa)3 kmb)4 kmc)5 kmd)6 kmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A worker reaches his factory 3 minutes late if his speed from his house to the factory is 5 km/hr. If he walks at a speed of 6 km/hr then he reaches the factory 7 minutes early the distance of the factory from his house isa)3 kmb)4 kmc)5 kmd)6 kmCorrect answer is option 'C'. Can you explain this answer?.
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