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A clerk starts from his house with a speed of 12 kmh and reaches the office 3 min late. Next day he increases speed 1 kmh and reaches the office 3 min earlier. Find the distance between his house and office?
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A clerk starts from his house with a speed of 12 kmh and reaches the o...
Analysis:
- Let the distance between the clerk's house and office be D km.
- Let the usual time taken to travel from home to office be T hours.
- According to the given information:
- Speed = 12 km/h, arrives 3 minutes late
- Speed = 13 km/h, arrives 3 minutes early

Calculations:
- When the clerk travels at 12 km/h, he arrives 3 minutes late. This can be represented as:
- T = D/12 + 3/60
- When the clerk travels at 13 km/h, he arrives 3 minutes early. This can be represented as:
- T = D/13 - 3/60
- Since the time taken for both scenarios is the same, we can equate the two equations:
- D/12 + 3/60 = D/13 - 3/60
- Solving the above equation, we get:
- D = 36 km

Conclusion:
- Therefore, the distance between the clerk's house and office is 36 km.
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A clerk starts from his house with a speed of 12 kmh and reaches the office 3 min late. Next day he increases speed 1 kmh and reaches the office 3 min earlier. Find the distance between his house and office?
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