Location of B is north of A and location of C is east of A. The distan...
Here is the arrangement.
Applying the Pythagoras theorem:
BC2 = AB2 + AC2 = 52 + 122 =25 + 144 = 169.
So BC = 13.
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Location of B is north of A and location of C is east of A. The distan...
Given information:
- Location of B is north of A
- Location of C is east of A
- Distance AB = 5 km
- Distance AC = 12 km
To find the shortest distance between B and C, we can use the Pythagorean theorem.
1. Drawing a diagram:
Let's draw a diagram to visualize the positions of A, B, and C. Assume that A is at the origin (0,0) on a coordinate plane.
C
|
|
A--------B
2. Finding the coordinates of A, B, and C:
Since B is north of A, its y-coordinate will be greater than A's y-coordinate. Let's assume B's coordinates as (0, yB).
Since C is east of A, its x-coordinate will be greater than A's x-coordinate. Let's assume C's coordinates as (xC, 0).
3. Using the distance formula:
The distance between two points (x1, y1) and (x2, y2) is given by the distance formula:
d = √((x2 - x1)^2 + (y2 - y1)^2)
Applying the distance formula for AB and AC:
AB = √((0 - 0)^2 + (yB - 0)^2) = √(yB^2)
AC = √((xC - 0)^2 + (0 - 0)^2) = √(xC^2)
4. Applying the given distances:
From the given information, AB = 5 km and AC = 12 km. Substituting these values in the above equations:
√(yB^2) = 5
√(xC^2) = 12
Squaring both sides:
yB^2 = 25
xC^2 = 144
5. Finding the shortest distance between B and C:
The shortest distance between B and C is the hypotenuse of the right-angled triangle formed by AB and AC. Using the Pythagorean theorem:
shortest distance = √(AB^2 + AC^2)
= √(5^2 + 12^2)
= √(25 + 144)
= √169
= 13 km
Therefore, the shortest distance between the locations B and C is 13 km.
Hence, the correct answer is option 'B'.
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