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A stone falls really under gravity it cover distance H1 H2 and S3 in the first 5 seconds the next 5 second and the next 5 seconds respectively the relation between H1 H2 and s3 is?
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Relation between H1, H2, and S3 for a Falling Stone
The relation between the distances covered by a falling stone in the first 5 seconds (H1), the next 5 seconds (H2), and the next 5 seconds after that (S3) can be explained using the equations of motion.
Equations of Motion
When an object falls under gravity, its motion can be described using the equations of motion. The equations are:
1. s = ut + (1/2)at^2
2. v = u + at
3. v^2 = u^2 + 2as
Where:
- s is the displacement
- u is the initial velocity
- v is the final velocity
- a is the acceleration
- t is the time
Relation between H1, H2, and S3
1. For the first 5 seconds:
- Let the initial velocity be 0 (stone dropped)
- Using the first equation of motion, H1 = (1/2)g(5)^2 = 25g
2. For the next 5 seconds:
- The stone starts from rest at the end of the first 5 seconds
- Using the first equation of motion, H2 = (1/2)g(5)^2 = 25g
3. For the next 5 seconds after that:
- The stone starts from rest at the end of the second 5 seconds
- Using the first equation of motion, S3 = (1/2)g(5)^2 = 25g
Therefore, the relation between H1, H2, and S3 is:
H1 = H2 = S3 = 25g
This means that the distances covered by the falling stone in each consecutive 5-second interval are equal and are given by 25 times the acceleration due to gravity.
The relation between the distances covered by a falling stone in the first 5 seconds (H1), the next 5 seconds (H2), and the next 5 seconds after that (S3) can be explained using the equations of motion.
Equations of Motion
When an object falls under gravity, its motion can be described using the equations of motion. The equations are:
1. s = ut + (1/2)at^2
2. v = u + at
3. v^2 = u^2 + 2as
Where:
- s is the displacement
- u is the initial velocity
- v is the final velocity
- a is the acceleration
- t is the time
Relation between H1, H2, and S3
1. For the first 5 seconds:
- Let the initial velocity be 0 (stone dropped)
- Using the first equation of motion, H1 = (1/2)g(5)^2 = 25g
2. For the next 5 seconds:
- The stone starts from rest at the end of the first 5 seconds
- Using the first equation of motion, H2 = (1/2)g(5)^2 = 25g
3. For the next 5 seconds after that:
- The stone starts from rest at the end of the second 5 seconds
- Using the first equation of motion, S3 = (1/2)g(5)^2 = 25g
Therefore, the relation between H1, H2, and S3 is:
H1 = H2 = S3 = 25g
This means that the distances covered by the falling stone in each consecutive 5-second interval are equal and are given by 25 times the acceleration due to gravity.
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A stone falls really under gravity it cover distance H1 H2 and S3 in the first 5 seconds the next 5 second and the next 5 seconds respectively the relation between H1 H2 and s3 is?
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A stone falls really under gravity it cover distance H1 H2 and S3 in the first 5 seconds the next 5 second and the next 5 seconds respectively the relation between H1 H2 and s3 is? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A stone falls really under gravity it cover distance H1 H2 and S3 in the first 5 seconds the next 5 second and the next 5 seconds respectively the relation between H1 H2 and s3 is? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stone falls really under gravity it cover distance H1 H2 and S3 in the first 5 seconds the next 5 second and the next 5 seconds respectively the relation between H1 H2 and s3 is?.
A stone falls really under gravity it cover distance H1 H2 and S3 in the first 5 seconds the next 5 second and the next 5 seconds respectively the relation between H1 H2 and s3 is? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A stone falls really under gravity it cover distance H1 H2 and S3 in the first 5 seconds the next 5 second and the next 5 seconds respectively the relation between H1 H2 and s3 is? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stone falls really under gravity it cover distance H1 H2 and S3 in the first 5 seconds the next 5 second and the next 5 seconds respectively the relation between H1 H2 and s3 is?.
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