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A stone falls under gravity and covers h1 distance from time t=2 to 4 sec and h2 distance from t=6 to 8 sec. find relation between h1 and h2?
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A stone falls under gravity and covers h1 distance from time t=2 to 4 ...


Relation between h1 and h2 in a Falling Stone Scenario



Given Information:

- The stone falls under gravity and covers h1 distance from time t=2 to 4 sec.
- The stone covers h2 distance from t=6 to 8 sec.


Analysis:

- The distance covered by a falling object under gravity can be calculated using the formula:
\[ h = \frac{1}{2} g t^2 \]
where h is the distance covered, g is the acceleration due to gravity, and t is the time.
- We know that the acceleration due to gravity is constant (approximately 9.81 m/s^2).


Finding the Relation between h1 and h2:

- Let's calculate the distances covered by the stone during the time intervals given:
- For time interval from t=2 to 4 sec:
\[ h1 = \frac{1}{2} \times 9.81 \times (4^2 - 2^2) \]
\[ h1 = 9.81 \times 12 = 117.72 \text{ m} \]
- For time interval from t=6 to 8 sec:
\[ h2 = \frac{1}{2} \times 9.81 \times (8^2 - 6^2) \]
\[ h2 = 9.81 \times 8 = 78.48 \text{ m} \]
- Therefore, the relation between h1 and h2 can be expressed as:
\[ h1 = \frac{3}{2} \times h2 \]


Conclusion:

- We have determined that the distance covered by the stone during the time intervals given follows the relation:
\[ h1 = \frac{3}{2} \times h2 \]
- This relationship highlights the consistent behavior of falling objects under gravity during different time intervals.
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A stone falls under gravity and covers h1 distance from time t=2 to 4 sec and h2 distance from t=6 to 8 sec. find relation between h1 and h2?
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