Mr.Jones gave 40% of the money he had to his wife. He also gave 20% of...
Let the initial amount be x,
Amount given to his wife =(40/100)x=2x/5
Balance = (x-(2x/5)) = 3x/5
Amount given to his wife = (20/100)*(3x/5) = 3x/25
Balance = 3x/5-3x/25 = 12x/25
Amountt spent on miscellaneous items = (1/2)*(12x/25) = 6x/25 which is equal to 12000
Hence,
=> 6x/25 = 12000
=> x = 50000
Hence (C) is the correcr answer.
View all questions of this test
Mr.Jones gave 40% of the money he had to his wife. He also gave 20% of...
Given:
- Mr. Jones gave 40% of his money to his wife.
- He gave 20% of the remaining amount to his 3 sons.
- Half of the amount now left was spent on miscellaneous items.
- The remaining amount left was Rs. 12000.
To find:
- How much money did Mr. Jones have initially?
Solution:
Let's assume that Mr. Jones initially had x amount of money.
1. Mr. Jones gave 40% of his money to his wife.
- So, he gave 0.4x amount of money to his wife.
- Now, he has 0.6x amount of money left.
2. He gave 20% of the remaining amount to his 3 sons.
- So, he gave 0.2(0.6x) amount of money to his 3 sons.
- Now, he has 0.6x - 0.12x = 0.48x amount of money left.
3. Half of the amount now left was spent on miscellaneous items.
- So, he spent 0.24x amount of money on miscellaneous items.
- Now, he has 0.24x amount of money left.
4. The remaining amount left was Rs. 12000.
- So, 0.24x = 12000.
- Solving for x, we get x = Rs. 50000.
Therefore, Mr. Jones had initially Rs. 50000. Answer: Option C.
Mr.Jones gave 40% of the money he had to his wife. He also gave 20% of...
Let the initial amount be x,
Amount given to his wife =(40/100)x=2x/5
Balance = (x-(2x/5)) = 3x/5
Amount given to his wife = (20/100)*(3x/5) = 3x/25
Balance = 3x/5-3x/25 = 12x/25
Amountt spent on miscellaneous items = (1/2)*(12x/25) = 6x/25 which is equal to 12000
Hence,
=> 6x/25 = 12000
=> x = 50000
Hence (C) is the correcr answer.