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The reaction of so lid XeF2 with AsF5 in 1:1 ratio affords:
- a)XeF4 and AsF3
- b)XeF6 and AsF3
- c)[XeF]+[AsF6]–
- d)[Xe2F3]+[AsF6]–
Correct answer is option 'C'. Can you explain this answer?
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The reaction of so lid XeF2 with AsF5 in 1:1 ratio affords:a)XeF4 and ...
Formation of [XeF][AsF6]
When solid XeF2 reacts with AsF5 in a 1:1 ratio, the following reaction takes place:
XeF2 + AsF5 → [XeF][AsF6]
Here, the product formed is [XeF][AsF6] which is a complex compound.
Explanation:
- XeF2 is a binary compound of xenon and fluorine, whereas AsF5 is a binary compound of arsenic and fluorine.
- When they react in a 1:1 ratio, one mole of XeF2 reacts with one mole of AsF5 to form the product.
- The product formed is [XeF][AsF6], which is a complex compound.
- In this compound, XeF+ ion acts as a Lewis acid and AsF6- ion acts as a Lewis base.
- The xenon atom in XeF+ ion has a vacant 5d orbital, which can accept a pair of electrons from AsF6- ion to form a coordinate covalent bond.
- Thus, the compound [XeF][AsF6] is formed, which is a stable complex compound.
Conclusion:
The reaction of solid XeF2 with AsF5 in a 1:1 ratio leads to the formation of a complex compound [XeF][AsF6].
When solid XeF2 reacts with AsF5 in a 1:1 ratio, the following reaction takes place:
XeF2 + AsF5 → [XeF][AsF6]
Here, the product formed is [XeF][AsF6] which is a complex compound.
Explanation:
- XeF2 is a binary compound of xenon and fluorine, whereas AsF5 is a binary compound of arsenic and fluorine.
- When they react in a 1:1 ratio, one mole of XeF2 reacts with one mole of AsF5 to form the product.
- The product formed is [XeF][AsF6], which is a complex compound.
- In this compound, XeF+ ion acts as a Lewis acid and AsF6- ion acts as a Lewis base.
- The xenon atom in XeF+ ion has a vacant 5d orbital, which can accept a pair of electrons from AsF6- ion to form a coordinate covalent bond.
- Thus, the compound [XeF][AsF6] is formed, which is a stable complex compound.
Conclusion:
The reaction of solid XeF2 with AsF5 in a 1:1 ratio leads to the formation of a complex compound [XeF][AsF6].
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The reaction of so lid XeF2 with AsF5 in 1:1 ratio affords:a)XeF4 and ...
Arsenic(V) fluoride react with xenon difluoride to produce fluoride-hexafluoroarsenate(V) xenon(II) and difluoride-hexafluoroarsenate(V) dixenon(II). The reaction is conducted in a liquid BrF5.
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The reaction of so lid XeF2 with AsF5 in 1:1 ratio affords:a)XeF4 and AsF3b)XeF6 and AsF3c)[XeF]+[AsF6]–d)[Xe2F3]+[AsF6]–Correct answer is option 'C'. Can you explain this answer?
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The reaction of so lid XeF2 with AsF5 in 1:1 ratio affords:a)XeF4 and AsF3b)XeF6 and AsF3c)[XeF]+[AsF6]–d)[Xe2F3]+[AsF6]–Correct answer is option 'C'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The reaction of so lid XeF2 with AsF5 in 1:1 ratio affords:a)XeF4 and AsF3b)XeF6 and AsF3c)[XeF]+[AsF6]–d)[Xe2F3]+[AsF6]–Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The reaction of so lid XeF2 with AsF5 in 1:1 ratio affords:a)XeF4 and AsF3b)XeF6 and AsF3c)[XeF]+[AsF6]–d)[Xe2F3]+[AsF6]–Correct answer is option 'C'. Can you explain this answer?.
The reaction of so lid XeF2 with AsF5 in 1:1 ratio affords:a)XeF4 and AsF3b)XeF6 and AsF3c)[XeF]+[AsF6]–d)[Xe2F3]+[AsF6]–Correct answer is option 'C'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The reaction of so lid XeF2 with AsF5 in 1:1 ratio affords:a)XeF4 and AsF3b)XeF6 and AsF3c)[XeF]+[AsF6]–d)[Xe2F3]+[AsF6]–Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The reaction of so lid XeF2 with AsF5 in 1:1 ratio affords:a)XeF4 and AsF3b)XeF6 and AsF3c)[XeF]+[AsF6]–d)[Xe2F3]+[AsF6]–Correct answer is option 'C'. Can you explain this answer?.
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