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A standard cell of 1.0185 V is used with a slide wire potentiometer. The balance was obtained at 60 cm. When an unknown emf was connected, the balance was obtained at 82 cm. What is the magnitude of unknownemf?
- a)1.39 V
- b)0.75 V
- c)13.9 V
- d)7.45 V
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A standard cell of 1.0185 V is used with a slide wire potentiometer. T...
Given that,
Standard voltage Es = 1.0185V
The balance obtained at 60 cm.
Resistance Rs = 60Ω
Working current 
Voltage corresponding to 82 cm,
V = 0.0169 × 82 = 1.39V =
Most Upvoted Answer
A standard cell of 1.0185 V is used with a slide wire potentiometer. T...
Given Information:
Standard cell voltage, Vₚ = 1.0185 V
Balance length with standard cell, l₁ = 60 cm
Balance length with unknown emf, l₂ = 82 cm
To Find: Magnitude of unknown emf
Solution:
Let the unknown emf be Vᵤ.
The potential gradient along the slide wire potentiometer is given by:
V/l = Vₚ/L
where,
V = Potential difference along the wire
l = Length of the wire
L = Total length of the wire
Using the above relation, we can find the potential difference along the wire when the standard cell is connected.
When the standard cell is connected, the potential difference along the wire is given by:
V₁/l₁ = Vₚ/L
=> V₁ = l₁ Vₚ/L
When the unknown emf is connected, the potential difference along the wire is given by:
V₂/l₂ = Vₚ/L + Vᵤ/L₂
=> V₂ = l₂ Vₚ/L + l₂ Vᵤ/L₂
At balance condition, V₁ = V₂
=> l₁ Vₚ/L = l₂ Vₚ/L + l₂ Vᵤ/L₂
=> Vᵤ = (l₁ - l₂) Vₚ/(L - L₂)
Substituting the given values, we get:
Vᵤ = (60 - 82) × 1.0185/(100 - 82) = -0.2211 V
Note: The negative sign indicates that the unknown emf is opposing the potential difference produced by the standard cell.
Therefore, the magnitude of unknown emf is:
|Vᵤ| = |-0.2211| = 0.2211 V
Rounding off to two decimal places, we get:
Magnitude of unknown emf = 0.22 V
Hence, option (A) 1.39 V is incorrect. Option (B) 0.75 V, option (C) 13.9 V, and option (D) 7.45 V are also incorrect.
Standard cell voltage, Vₚ = 1.0185 V
Balance length with standard cell, l₁ = 60 cm
Balance length with unknown emf, l₂ = 82 cm
To Find: Magnitude of unknown emf
Solution:
Let the unknown emf be Vᵤ.
The potential gradient along the slide wire potentiometer is given by:
V/l = Vₚ/L
where,
V = Potential difference along the wire
l = Length of the wire
L = Total length of the wire
Using the above relation, we can find the potential difference along the wire when the standard cell is connected.
When the standard cell is connected, the potential difference along the wire is given by:
V₁/l₁ = Vₚ/L
=> V₁ = l₁ Vₚ/L
When the unknown emf is connected, the potential difference along the wire is given by:
V₂/l₂ = Vₚ/L + Vᵤ/L₂
=> V₂ = l₂ Vₚ/L + l₂ Vᵤ/L₂
At balance condition, V₁ = V₂
=> l₁ Vₚ/L = l₂ Vₚ/L + l₂ Vᵤ/L₂
=> Vᵤ = (l₁ - l₂) Vₚ/(L - L₂)
Substituting the given values, we get:
Vᵤ = (60 - 82) × 1.0185/(100 - 82) = -0.2211 V
Note: The negative sign indicates that the unknown emf is opposing the potential difference produced by the standard cell.
Therefore, the magnitude of unknown emf is:
|Vᵤ| = |-0.2211| = 0.2211 V
Rounding off to two decimal places, we get:
Magnitude of unknown emf = 0.22 V
Hence, option (A) 1.39 V is incorrect. Option (B) 0.75 V, option (C) 13.9 V, and option (D) 7.45 V are also incorrect.
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Community Answer
A standard cell of 1.0185 V is used with a slide wire potentiometer. T...
In a slide wire potentiometer
unknown V= STD cell voltage* Unknown V balancing length/STD cell balancing length
unknown V= STD cell voltage* Unknown V balancing length/STD cell balancing length
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A standard cell of 1.0185 V is used with a slide wire potentiometer. The balance was obtained at 60 cm. When an unknown emf was connected, the balance was obtained at 82 cm. What is the magnitude of unknownemf?a)1.39 Vb)0.75 Vc)13.9 Vd)7.45 VCorrect answer is option 'A'. Can you explain this answer?
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