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The probability of two persons of passing the interview are 1/3 and 3/5. Then calculate the probability that only one of them pass the interview ?

  • a)
    7/15

  • b)
    8/15

  • c)
    11/15

  • d)
    13/15

Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The probability of two persons of passing the interview are 1/3 and 3/...
(P = pass, F = fail)

ApassBfail + AfailBpass

PF + FP

1/3*2/5 + 2/3*3/5 = 8/15
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Most Upvoted Answer
The probability of two persons of passing the interview are 1/3 and 3/...
Solution:

We are given that the probability of first person passing the interview is 1/3 and the probability of second person passing the interview is 3/5.

Let A be the event that the first person passes the interview and B be the event that the second person passes the interview.

We need to find the probability that only one of them passes the interview. Let C be the event that only one of them passes the interview.

We can calculate the probability of C using the following formula:

P(C) = P(A) × P(B') + P(A') × P(B)

where P(B') is the probability of B not happening and P(A') is the probability of A not happening.

Now, we can substitute the values of P(A) and P(B) in the above formula:

P(C) = (1/3) × (2/5) + (2/3) × (3/5)

Simplifying the above expression, we get:

P(C) = 2/15 + 6/15

P(C) = 8/15

Therefore, the probability that only one of them passes the interview is 8/15.

Hence, the correct answer is option 'B'.
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The probability of two persons of passing the interview are 1/3 and 3/5. Then calculate the probability that only one of them pass the interview ?a)7/15b)8/15c)11/15d)13/15Correct answer is option 'B'. Can you explain this answer?
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