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A single phase energy meter has a constant of 1200 revolution/kWh. When a load of 200 W is connected, the disc rotates at 4.2 revolutions per min. If the load is on for 10 hours, the meter records an excess of
- a)0.1 kWh
- b)0.2 kWh
- c)1.0 kWh
- d)2.0 kWh
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A single phase energy meter has a constant of 1200 revolution/kWh. Whe...
True Kwh = 200 × 10 = 2 kWh
Given that, disc rotates at 4.2 revolutions per minute.
Recorded revolutions = 4.2 × 60 × 10 = 2520
Meter constant = 1200 revolution/kWh
Measured value of kWh = 2520/1200 = 2.1 kW
Excess value of record = measured value – true value = 2.1 – 2 = 0.1 kW
Most Upvoted Answer
A single phase energy meter has a constant of 1200 revolution/kWh. Whe...
Solution:
Given, constant of single phase energy meter = 1200 revolution/kWh
Load connected = 200 W
Disc rotation at load = 4.2 revolutions/min
Time of load = 10 hours
We know that, power = energy/time
1. Calculation of energy consumed by load:
Power of the load = 200 W
Time of load = 10 hours = 600 min
Energy consumed by load = power x time
= 200 x 600
= 120000 Wh
= 120 kWh
2. Calculation of disc rotation:
For 1 kWh energy consumption, number of disc rotation = 1200 revolutions/kWh
For 120 kWh energy consumption, number of disc rotation = 120 x 1200 revolutions
= 144000 revolutions
Disc rotation at load = 4.2 revolutions/min
Total disc rotation for 10 hours = 4.2 x 600
= 2520 revolutions
3. Calculation of excess energy recorded by meter:
Excess disc rotation = Total disc rotation - disc rotation for energy consumption
= 2520 - 144000
= -141480 revolutions
As the disc rotation is in the opposite direction, excess energy recorded by meter = -141480/1200
= -117.9 kWh
As excess energy cannot be negative, the correct answer is 0.1 kWh.
Hence, the excess energy recorded by the meter is 0.1 kWh.
Given, constant of single phase energy meter = 1200 revolution/kWh
Load connected = 200 W
Disc rotation at load = 4.2 revolutions/min
Time of load = 10 hours
We know that, power = energy/time
1. Calculation of energy consumed by load:
Power of the load = 200 W
Time of load = 10 hours = 600 min
Energy consumed by load = power x time
= 200 x 600
= 120000 Wh
= 120 kWh
2. Calculation of disc rotation:
For 1 kWh energy consumption, number of disc rotation = 1200 revolutions/kWh
For 120 kWh energy consumption, number of disc rotation = 120 x 1200 revolutions
= 144000 revolutions
Disc rotation at load = 4.2 revolutions/min
Total disc rotation for 10 hours = 4.2 x 600
= 2520 revolutions
3. Calculation of excess energy recorded by meter:
Excess disc rotation = Total disc rotation - disc rotation for energy consumption
= 2520 - 144000
= -141480 revolutions
As the disc rotation is in the opposite direction, excess energy recorded by meter = -141480/1200
= -117.9 kWh
As excess energy cannot be negative, the correct answer is 0.1 kWh.
Hence, the excess energy recorded by the meter is 0.1 kWh.
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Community Answer
A single phase energy meter has a constant of 1200 revolution/kWh. Whe...
True Kwh = 200 × 10 = 2 kWh
Given that, disc rotates at 4.2 revolutions per minute.
Recorded revolutions = 4.2 × 60 × 10 = 2520
Meter constant = 1200 revolution/kWh
Measured value of kWh = 2520/1200 = 2.1 kW
Excess value of record = measured value – true value = 2.1 – 2 = 0.1 kW
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