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From a pack of 52 cads, 2 cards are drawn at random. What is the probability of drawing such that there is at least 1 king?
- a)35/256
- b)33/220
- c)33/221
- d)23/190
- e)11/221
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
From a pack of 52 cads, 2 cards are drawn at random. What is the proba...
Case 1: 1 is king
4C1 * 48C1 / 52C2
Case 2: both are king
4C2 / 52C2
Add both cases.
4C1 * 48C1 / 52C2
Case 2: both are king
4C2 / 52C2
Add both cases.
Most Upvoted Answer
From a pack of 52 cads, 2 cards are drawn at random. What is the proba...
Calculating the Probability of Drawing at Least 1 King from a Pack of 52 Cards:
To calculate the probability of drawing at least 1 king from a pack of 52 cards, we need to consider two scenarios:
Scenario 1: Drawing 1 King and 1 Non-King Card
- There are 4 kings in a deck of 52 cards, so the probability of drawing 1 king = 4/52
- After drawing 1 king, there are 48 non-king cards left in the deck, so the probability of drawing 1 non-king card = 48/51
- Therefore, the probability of scenario 1 = (4/52) * (48/51)
Scenario 2: Drawing 2 Kings
- The probability of drawing the first king = 4/52
- After drawing the first king, there are 3 kings left in the deck and a total of 51 cards remaining, so the probability of drawing the second king = 3/51
- Therefore, the probability of scenario 2 = (4/52) * (3/51)
Calculating the Total Probability
- To find the total probability of drawing at least 1 king, we need to add the probabilities of scenario 1 and scenario 2
- Total probability = Probability of scenario 1 + Probability of scenario 2
- Total probability = (4/52) * (48/51) + (4/52) * (3/51)
- Total probability = 33/221
Therefore, the correct answer is option C) 33/221.
To calculate the probability of drawing at least 1 king from a pack of 52 cards, we need to consider two scenarios:
Scenario 1: Drawing 1 King and 1 Non-King Card
- There are 4 kings in a deck of 52 cards, so the probability of drawing 1 king = 4/52
- After drawing 1 king, there are 48 non-king cards left in the deck, so the probability of drawing 1 non-king card = 48/51
- Therefore, the probability of scenario 1 = (4/52) * (48/51)
Scenario 2: Drawing 2 Kings
- The probability of drawing the first king = 4/52
- After drawing the first king, there are 3 kings left in the deck and a total of 51 cards remaining, so the probability of drawing the second king = 3/51
- Therefore, the probability of scenario 2 = (4/52) * (3/51)
Calculating the Total Probability
- To find the total probability of drawing at least 1 king, we need to add the probabilities of scenario 1 and scenario 2
- Total probability = Probability of scenario 1 + Probability of scenario 2
- Total probability = (4/52) * (48/51) + (4/52) * (3/51)
- Total probability = 33/221
Therefore, the correct answer is option C) 33/221.
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From a pack of 52 cads, 2 cards are drawn at random. What is the probability of drawing such that there is at least 1 king?a)35/256b)33/220c)33/221d)23/190e)11/221Correct answer is option 'C'. Can you explain this answer?
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