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In a class 30% of the students opt for Math, 20% opt for Computers and 10% opt for both. A student is selected at random, find the probability that he has opted either Math or Computers.
- a)3/5
- b)2/5
- c)4/9
- d)6/11
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
In a class 30% of the students opt for Math, 20% opt for Computers and...
Prob. of math = 30/100 = 3/10, Prob. of computers = 20/100 = 1/5, prob. for both = 10/100 = 1/10
So required prob. = 3/5 + 1/5 – 1/10
So required prob. = 3/5 + 1/5 – 1/10
Most Upvoted Answer
In a class 30% of the students opt for Math, 20% opt for Computers and...
Given:
- 30% of the students opt for Math
- 20% of the students opt for Computers
- 10% of the students opt for both Math and Computers
To find the probability that a student has opted for either Math or Computers, we need to find the union of the two events: P(Math or Computers).
The formula for the union of two events is:
P(A or B) = P(A) + P(B) - P(A and B)
Let's calculate the probabilities step by step:
1. P(Math) = 30% = 0.3
2. P(Computers) = 20% = 0.2
3. P(Math and Computers) = 10% = 0.1
Using the formula for the union of two events, we can calculate the probability that a student has opted for either Math or Computers:
P(Math or Computers) = P(Math) + P(Computers) - P(Math and Computers)
= 0.3 + 0.2 - 0.1
= 0.4
Therefore, the probability that a student has opted for either Math or Computers is 0.4, which is equivalent to 2/5.
Hence, the correct answer is option B) 2/5.
- 30% of the students opt for Math
- 20% of the students opt for Computers
- 10% of the students opt for both Math and Computers
To find the probability that a student has opted for either Math or Computers, we need to find the union of the two events: P(Math or Computers).
The formula for the union of two events is:
P(A or B) = P(A) + P(B) - P(A and B)
Let's calculate the probabilities step by step:
1. P(Math) = 30% = 0.3
2. P(Computers) = 20% = 0.2
3. P(Math and Computers) = 10% = 0.1
Using the formula for the union of two events, we can calculate the probability that a student has opted for either Math or Computers:
P(Math or Computers) = P(Math) + P(Computers) - P(Math and Computers)
= 0.3 + 0.2 - 0.1
= 0.4
Therefore, the probability that a student has opted for either Math or Computers is 0.4, which is equivalent to 2/5.
Hence, the correct answer is option B) 2/5.
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In a class 30% of the students opt for Math, 20% opt for Computers and 10% opt for both. A student is selected at random, find the probability that he has opted either Math or Computers.a)3/5b)2/5c)4/9d)6/11e)None of theseCorrect answer is option 'B'. Can you explain this answer?
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