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A bag contains 6 red balls and 8 green balls. Two balls are drawn at random one after one with replacement. What is the probability that
Q.
Both the balls are red
  • a)
    14/49
  • b)
    9/49
  • c)
    11/49
  • d)
    12/49
  • e)
    None of these
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A bag contains 6 red balls and 8 green balls. Two balls are drawn at r...
P = (6/14)*(6/14)
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Most Upvoted Answer
A bag contains 6 red balls and 8 green balls. Two balls are drawn at r...
Solution:

Given,
Total number of balls = 6+8 = 14
Number of red balls = 6

To find the probability of getting two red balls,

Let A be the event of getting a red ball in the first draw.
Let B be the event of getting a red ball in the second draw.

Since the two draws are made with replacement, the probability of getting a red ball in each draw is the same and can be calculated as follows:

P(A) = number of ways of getting a red ball in the first draw/total number of balls
= 6/14

P(B) = number of ways of getting a red ball in the second draw/total number of balls
= 6/14

To find the probability of getting two red balls, we need to find the probability of both A and B occurring.

P(A and B) = P(A) × P(B)
= (6/14) × (6/14)
= 36/196
= 9/49

Therefore, the probability of getting two red balls is 9/49.

Hence, option B is the correct answer.
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A bag contains 6 red balls and 8 green balls. Two balls are drawn at random one after one with replacement. What is the probability thatQ. Both the balls are reda)14/49b)9/49c)11/49d)12/49e)None of theseCorrect answer is option 'B'. Can you explain this answer?
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