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A bag contains 3 red balls and 8 blacks ball and another bag contains 5 red balls and 7 blacks balls, one ball is drawn at random from either of the bag, find the probability that the ball is red.
  • a)
    93/264
  • b)
    95/264
  • c)
    91/264
  • d)
    97/264
  • e)
    None of these
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A bag contains 3 red balls and 8 blacks ball and another bag contains ...
Probability = probability of selecting the bag and probability of selecting red ball
(1/2)*(3/11) + (1/2)*(5/12) = 91/264
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Most Upvoted Answer
A bag contains 3 red balls and 8 blacks ball and another bag contains ...
To find the probability that a red ball is drawn, we need to calculate the total number of red balls and the total number of balls in both bags.

Bag 1:
- Red balls: 3
- Black balls: 8
Total balls in Bag 1: 3 + 8 = 11

Bag 2:
- Red balls: 5
- Black balls: 7
Total balls in Bag 2: 5 + 7 = 12

Total number of red balls in both bags: 3 + 5 = 8
Total number of balls in both bags: 11 + 12 = 23

Probability of drawing a red ball = Number of favorable outcomes / Total number of possible outcomes

The favorable outcome in this case is drawing a red ball, so the number of favorable outcomes is 8.

The total number of possible outcomes is the total number of balls in both bags, which is 23.

Probability of drawing a red ball = 8 / 23

Simplifying the fraction, we get:

Probability of drawing a red ball = 8 / 23 = 91 / 264

Therefore, the correct answer is option C) 91/264.
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