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A basket contains 5 red 4 blue 3 green marbles. If two marbles picked up random, What is the probability that both are red?
- a)4/33
- b)5/33
- c)7/33
- d)8/33
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A basket contains 5 red 4 blue 3 green marbles. If two marbles picked ...
Total Marbles = 12
Probability = 5c2 / 12c2 = 5/33
Probability = 5c2 / 12c2 = 5/33
Most Upvoted Answer
A basket contains 5 red 4 blue 3 green marbles. If two marbles picked ...
To find the probability of picking two red marbles from the basket, we need to first determine the total number of marbles in the basket and then calculate the probability.
Step 1: Total number of marbles
The basket contains a total of 5 red marbles, 4 blue marbles, and 3 green marbles. So, the total number of marbles in the basket is:
5 red + 4 blue + 3 green = 12 marbles
Step 2: Probability of picking the first red marble
Out of the 12 marbles in the basket, 5 are red. Therefore, the probability of picking a red marble as the first one is:
P(Red1) = Number of red marbles / Total number of marbles
= 5 / 12
Step 3: Probability of picking the second red marble
After picking the first marble, there will be one less marble in the basket. Now, there are 4 red marbles left out of the 11 marbles. Therefore, the probability of picking a red marble as the second one is:
P(Red2) = Number of red marbles left / Total number of marbles left
= 4 / 11
Step 4: Probability of picking two red marbles
To find the probability of picking two red marbles, we multiply the probabilities of picking the first and second red marbles:
P(Both red) = P(Red1) * P(Red2)
= (5/12) * (4/11)
= 20/132
= 5/33
So, the probability that both marbles picked are red is 5/33.
Therefore, the correct answer is option 'B'.
Step 1: Total number of marbles
The basket contains a total of 5 red marbles, 4 blue marbles, and 3 green marbles. So, the total number of marbles in the basket is:
5 red + 4 blue + 3 green = 12 marbles
Step 2: Probability of picking the first red marble
Out of the 12 marbles in the basket, 5 are red. Therefore, the probability of picking a red marble as the first one is:
P(Red1) = Number of red marbles / Total number of marbles
= 5 / 12
Step 3: Probability of picking the second red marble
After picking the first marble, there will be one less marble in the basket. Now, there are 4 red marbles left out of the 11 marbles. Therefore, the probability of picking a red marble as the second one is:
P(Red2) = Number of red marbles left / Total number of marbles left
= 4 / 11
Step 4: Probability of picking two red marbles
To find the probability of picking two red marbles, we multiply the probabilities of picking the first and second red marbles:
P(Both red) = P(Red1) * P(Red2)
= (5/12) * (4/11)
= 20/132
= 5/33
So, the probability that both marbles picked are red is 5/33.
Therefore, the correct answer is option 'B'.
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A basket contains 5 red 4 blue 3 green marbles. If two marbles picked up random, What is the probability that both are red?a)4/33b)5/33c)7/33d)8/33Correct answer is option 'B'. Can you explain this answer?
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