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A parallel plate capacitor is charged from a cell and then isolated from it. The separation between the plates is now increased
  • a)
    The force of attraction between the plates will decrease 
  • b)
    The energy stored in the capacitor will increase 
  • c)
    The potential difference between the plates will decrease 
  • d)
    The field in the region between the plates will not change 
Correct answer is option 'B,D'. Can you explain this answer?
Most Upvoted Answer
A parallel plate capacitor is charged from a cell and then isolated fr...
Explanation:
When a parallel plate capacitor is charged from a cell and then isolated from it, several changes occur. Let's examine each option individually:

A) The force of attraction between the plates will decrease:
The force of attraction between the plates of a capacitor is given by the equation F = (Q^2) / (2εA), where Q is the charge on the plates, ε is the permittivity of the medium between the plates, and A is the area of the plates. The force of attraction is directly proportional to the charge on the plates. Therefore, when the separation between the plates is increased, the charge on the plates remains constant, and the force of attraction between the plates decreases. So, option A is correct.

B) The energy stored in the capacitor will increase:
The energy stored in a capacitor is given by the equation U = (1/2) (Q^2) / C, where U is the energy stored, Q is the charge on the plates, and C is the capacitance of the capacitor. The energy stored is directly proportional to the square of the charge on the plates. When the separation between the plates is increased, the capacitance of the capacitor decreases according to the equation C = (εA) / d, where ε is the permittivity of the medium between the plates and d is the separation between the plates. As the capacitance decreases, the energy stored in the capacitor increases. So, option B is correct.

C) The potential difference between the plates will decrease:
The potential difference between the plates of a capacitor is given by the equation V = Q / C, where V is the potential difference, Q is the charge on the plates, and C is the capacitance of the capacitor. When the separation between the plates is increased, the capacitance of the capacitor decreases, as mentioned earlier. As a result, the potential difference between the plates also decreases according to the equation V = Q / C. So, option C is correct.

D) The electric field in the region between the plates will not change:
The electric field between the plates of a capacitor is given by the equation E = V / d, where E is the electric field, V is the potential difference between the plates, and d is the separation between the plates. When the separation between the plates is increased, the potential difference between the plates decreases, but the separation also increases proportionally. As a result, the electric field between the plates remains constant. So, option D is correct.

In conclusion, the correct options are B and D: The energy stored in the capacitor will increase, and the electric field in the region between the plates will not change.
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A parallel plate capacitor is charged from a cell and then isolated fr...
The correct answers are: The field in the region between the plates will not change, The energy stored in the capacitor will increase
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A parallel plate capacitor is charged from a cell and then isolated from it. The separation between the plates is now increaseda)The force of attraction between the plates will decreaseb)The energy stored in the capacitor will increasec)The potential difference between the plates will decreased)The field in the region between the plates will not changeCorrect answer is option 'B,D'. Can you explain this answer?
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A parallel plate capacitor is charged from a cell and then isolated from it. The separation between the plates is now increaseda)The force of attraction between the plates will decreaseb)The energy stored in the capacitor will increasec)The potential difference between the plates will decreased)The field in the region between the plates will not changeCorrect answer is option 'B,D'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A parallel plate capacitor is charged from a cell and then isolated from it. The separation between the plates is now increaseda)The force of attraction between the plates will decreaseb)The energy stored in the capacitor will increasec)The potential difference between the plates will decreased)The field in the region between the plates will not changeCorrect answer is option 'B,D'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A parallel plate capacitor is charged from a cell and then isolated from it. The separation between the plates is now increaseda)The force of attraction between the plates will decreaseb)The energy stored in the capacitor will increasec)The potential difference between the plates will decreased)The field in the region between the plates will not changeCorrect answer is option 'B,D'. Can you explain this answer?.
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