A 132 litres of mixture contains milk and water in the ratio 5 : 7. Ho...
A) 36 litres Explanation: Milk in original = (5/12) * 132 = 55 l, so water = 132 – 55 = 77 l Let x l of milk to be added, so (55+x)/77 = 13/11 Solve, x = 36
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A 132 litres of mixture contains milk and water in the ratio 5 : 7. Ho...
Problem:
A 132 litres of mixture contains milk and water in the ratio 5 : 7. How much milk need to be added to this mixture so that the new ratio is 13 : 11 respectively?
Solution:
Let us assume that x litres of milk need to be added to obtain the new ratio.
Given, the initial ratio of milk and water in the mixture = 5:7
Therefore, the quantity of milk in the mixture = $\dfrac{5}{12}$ x 132 = 55 litres
Quantity of water in the mixture = $\dfrac{7}{12}$ x 132 = 77 litres
Now, the new ratio of milk and water in the mixture is 13:11
Therefore, the quantity of milk required in the new mixture = $\dfrac{13}{24}$ x (132 + x) litres
Quantity of water required in the new mixture = $\dfrac{11}{24}$ x (132 + x) litres
According to the problem, the quantity of milk added to the mixture is x litres.
Therefore, the equation can be formed as follows:
$\dfrac{13}{24}$ x (132 + x) = 55 + x
On solving the above equation, we get x = 36 litres
Therefore, 36 litres of milk need to be added to the mixture to obtain the new ratio of milk and water in the mixture.
Hence, the correct option is (a) 36 litres.