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Find the mobility  (in cm2/volt-sec) of e- in copper assuming that each atom contributes one free e- for conduction.
Resistivity of copper is 2.7 x 10-6 ohm-cm.
Atomic weight of copper is 63.54.
Density of copper = 8.96 gm/cm3
Avogadro's number = 6.025 x 1023
Electronic charge = 1.6 x 10-19 coulomb.
    Correct answer is '27.25'. Can you explain this answer?
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    Given:
    Resistivity of copper (ρ) = 2.7 x 10^-6 ohm-cm
    Atomic weight of copper (A) = 63.54
    Density of copper (ρ) = 8.96 gm/cm^3
    Avogadro's number (N) = 6.025 x 10^23
    Electronic charge (e) = 1.6 x 10^-19 coulomb

    Formula:
    The mobility (μ) of a charge carrier is given by the equation:
    μ = σ / (n * e)
    where σ is the electrical conductivity, n is the charge carrier concentration, and e is the electronic charge.

    Solution:
    Step 1: Calculate the charge carrier concentration (n):
    The charge carrier concentration (n) can be calculated using the formula:
    n = N * (ρ / A) * (1 / ρ)
    where N is Avogadro's number, ρ is the density, and A is the atomic weight.

    Substituting the given values into the formula:
    n = (6.025 x 10^23) * (8.96 gm/cm^3) * (1 cm^3 / 63.54 gm)
    n = 8.493 x 10^22 cm^-3

    Step 2: Calculate the electrical conductivity (σ):
    The electrical conductivity (σ) can be calculated using the formula:
    σ = 1 / ρ
    where ρ is the resistivity.

    Substituting the given value into the formula:
    σ = 1 / (2.7 x 10^-6 ohm-cm)
    σ = 3.703 x 10^5 (ohm-cm)^-1

    Step 3: Calculate the mobility (μ):
    The mobility (μ) can be calculated using the formula:
    μ = σ / (n * e)
    where σ is the electrical conductivity, n is the charge carrier concentration, and e is the electronic charge.

    Substituting the calculated values into the formula:
    μ = (3.703 x 10^5 (ohm-cm)^-1) / ((8.493 x 10^22 cm^-3) * (1.6 x 10^-19 coulomb))
    μ ≈ 27.25 cm^2/V-sec

    Therefore, the mobility of electrons in copper is approximately 27.25 cm^2/V-sec.
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    Find the mobility (in cm2/volt-sec) of e- in copper assuming that each atom contributes one free e- for conduction.Resistivity of copper is 2.7 x 10-6 ohm-cm.Atomic weight of copper is 63.54.Density of copper = 8.96 gm/cm3Avogadro's number = 6.025 x 1023Electronic charge = 1.6 x 10-19 coulomb.Correct answer is '27.25'. Can you explain this answer?
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    Find the mobility (in cm2/volt-sec) of e- in copper assuming that each atom contributes one free e- for conduction.Resistivity of copper is 2.7 x 10-6 ohm-cm.Atomic weight of copper is 63.54.Density of copper = 8.96 gm/cm3Avogadro's number = 6.025 x 1023Electronic charge = 1.6 x 10-19 coulomb.Correct answer is '27.25'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Find the mobility (in cm2/volt-sec) of e- in copper assuming that each atom contributes one free e- for conduction.Resistivity of copper is 2.7 x 10-6 ohm-cm.Atomic weight of copper is 63.54.Density of copper = 8.96 gm/cm3Avogadro's number = 6.025 x 1023Electronic charge = 1.6 x 10-19 coulomb.Correct answer is '27.25'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the mobility (in cm2/volt-sec) of e- in copper assuming that each atom contributes one free e- for conduction.Resistivity of copper is 2.7 x 10-6 ohm-cm.Atomic weight of copper is 63.54.Density of copper = 8.96 gm/cm3Avogadro's number = 6.025 x 1023Electronic charge = 1.6 x 10-19 coulomb.Correct answer is '27.25'. Can you explain this answer?.
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