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A mixture containing milk and water in the ratio 3:2 and another mixture contains them in the ratio 4:5. How many litres of the later must be mixed with 3 litres of the former so that the resulting mixture may contain equal quantities of milk and water?
- a)3.3/4 litre
- b)4.1/2 litre
- c)5.2/3 litre
- d)5.2/5 litre
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
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A mixture containing milk and water in the ratio 3:2 and another mixtu...
Answer – d) 5.2/5 litre Explanation : milk = 3*3/5 = 9/5 litre and water = 3*2/5 = 6/5 litre (in first mixture) milk = 4k/9 and water = 5k/9 litres in second mixture, so 9/5 + 4k/9 = 6/5 + 5k/9, we get k = 27/5 litre
Most Upvoted Answer
A mixture containing milk and water in the ratio 3:2 and another mixtu...
To solve this problem, we need to set up a system of equations based on the given information. Let's denote the quantity of milk in the first mixture as 3x and the quantity of water as 2x. Similarly, for the second mixture, let's denote the quantity of milk as 4y and the quantity of water as 5y.
We are given that 3 litres of the first mixture are mixed with some quantity of the second mixture. Let's assume that the quantity of the second mixture added is z litres. So, we have:
Milk in the resulting mixture = 3x + 4y
Water in the resulting mixture = 2x + 5y
Since the resulting mixture must contain equal quantities of milk and water, we can set up the following equation:
3x + 4y = 2x + 5y
Simplifying this equation, we get:
x = y
This means that the ratio of milk to water in both mixtures is the same, and we can equate the ratios:
3x/2x = 4y/5y
Cross-multiplying, we get:
15x = 8x
Simplifying this equation, we get:
7x = 0
Since x cannot be equal to 0, this equation has no solution. Therefore, it is not possible to mix the two given mixtures in such a way that the resulting mixture contains equal quantities of milk and water.
Hence, the correct answer is option (e) None of these.
We are given that 3 litres of the first mixture are mixed with some quantity of the second mixture. Let's assume that the quantity of the second mixture added is z litres. So, we have:
Milk in the resulting mixture = 3x + 4y
Water in the resulting mixture = 2x + 5y
Since the resulting mixture must contain equal quantities of milk and water, we can set up the following equation:
3x + 4y = 2x + 5y
Simplifying this equation, we get:
x = y
This means that the ratio of milk to water in both mixtures is the same, and we can equate the ratios:
3x/2x = 4y/5y
Cross-multiplying, we get:
15x = 8x
Simplifying this equation, we get:
7x = 0
Since x cannot be equal to 0, this equation has no solution. Therefore, it is not possible to mix the two given mixtures in such a way that the resulting mixture contains equal quantities of milk and water.
Hence, the correct answer is option (e) None of these.
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A mixture containing milk and water in the ratio 3:2 and another mixture contains them in the ratio 4:5. How many litres of the later must be mixed with 3 litres of the former so that the resulting mixture may contain equal quantities of milk and water?a)3.3/4 litreb)4.1/2 litrec)5.2/3 litred)5.2/5 litree)None of theseCorrect answer is option 'D'. Can you explain this answer?
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