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Refractive index of glass is 1.5. Find the wavelength of a beam of light with a frequency of 1014 Hz in glass. Assume velocity of light is 3 x 108 m/sec in vacuum.
- a)4 μm
- b)3 μm
- c)2 μm
- d)1 μm
Correct answer is option 'C'. Can you explain this answer?
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Refractive index of glass is 1.5. Find the wavelength of a beam of lig...
Given, μ = 1.6, f = 1014 Hz, v = 3 x 108 m/sec.
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Refractive index of glass is 1.5. Find the wavelength of a beam of lig...
The refractive index of a medium is the ratio of the speed of light in vacuum to the speed of light in that medium. In this case, the refractive index of glass is given as 1.5.
The velocity of light in vacuum is given as 3 x 10^8 m/s.
To find the wavelength of the light in glass, we can use the formula:
wavelength = velocity of light in vacuum / (refractive index * frequency)
Given that the frequency is 1014 Hz, we can substitute the values into the formula:
wavelength = (3 x 10^8 m/s) / (1.5 * 1014 Hz)
Simplifying the expression, we get:
wavelength = (3 x 10^8 m/s) / (1.5 x 10^14 Hz)
Now, let's simplify the numerator and denominator separately:
Numerator: 3 x 10^8 m/s = 3 x 10^8 x 10^6 μm/s = 3 x 10^14 μm/s
Denominator: 1.5 x 10^14 Hz = 1.5 x 10^14 x 10^-6 μm/s = 1.5 x 10^8 μm/s
Substituting these values back into the expression:
wavelength = (3 x 10^14 μm/s) / (1.5 x 10^8 μm/s)
Cancelling out the units, we get:
wavelength = (3 x 10^14) / (1.5 x 10^8) μm
Simplifying the expression, we get:
wavelength = 2 μm
Therefore, the wavelength of the light in glass with a frequency of 1014 Hz is 2 μm. Thus, option C is the correct answer.
The velocity of light in vacuum is given as 3 x 10^8 m/s.
To find the wavelength of the light in glass, we can use the formula:
wavelength = velocity of light in vacuum / (refractive index * frequency)
Given that the frequency is 1014 Hz, we can substitute the values into the formula:
wavelength = (3 x 10^8 m/s) / (1.5 * 1014 Hz)
Simplifying the expression, we get:
wavelength = (3 x 10^8 m/s) / (1.5 x 10^14 Hz)
Now, let's simplify the numerator and denominator separately:
Numerator: 3 x 10^8 m/s = 3 x 10^8 x 10^6 μm/s = 3 x 10^14 μm/s
Denominator: 1.5 x 10^14 Hz = 1.5 x 10^14 x 10^-6 μm/s = 1.5 x 10^8 μm/s
Substituting these values back into the expression:
wavelength = (3 x 10^14 μm/s) / (1.5 x 10^8 μm/s)
Cancelling out the units, we get:
wavelength = (3 x 10^14) / (1.5 x 10^8) μm
Simplifying the expression, we get:
wavelength = 2 μm
Therefore, the wavelength of the light in glass with a frequency of 1014 Hz is 2 μm. Thus, option C is the correct answer.
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Refractive index of glass is 1.5. Find the wavelength of a beam of light with a frequency of 1014 Hz in glass. Assume velocity of light is 3 x 108 m/sec in vacuum.a)4 μmb)3 μmc)2 μmd)1 μmCorrect answer is option 'C'. Can you explain this answer?
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Refractive index of glass is 1.5. Find the wavelength of a beam of light with a frequency of 1014 Hz in glass. Assume velocity of light is 3 x 108 m/sec in vacuum.a)4 μmb)3 μmc)2 μmd)1 μmCorrect answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Refractive index of glass is 1.5. Find the wavelength of a beam of light with a frequency of 1014 Hz in glass. Assume velocity of light is 3 x 108 m/sec in vacuum.a)4 μmb)3 μmc)2 μmd)1 μmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Refractive index of glass is 1.5. Find the wavelength of a beam of light with a frequency of 1014 Hz in glass. Assume velocity of light is 3 x 108 m/sec in vacuum.a)4 μmb)3 μmc)2 μmd)1 μmCorrect answer is option 'C'. Can you explain this answer?.
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