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A man purchased 40 fruits; apples and oranges for Rs 17. Had he purchased as many as oranges as apples and as many apples as oranges, he would have paid Rs 15. Find the cost of one pair of an apple and an orange.
  • a)
    70 paise
  • b)
    80 paise
  • c)
    90 paise
  • d)
    Rupee 1
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A man purchased 40 fruits; apples and oranges for Rs 17. Had he purcha...
Man buys x apples at m price and y oranges at n price, then we get the 2 equations,
x+y=40------------ (i)
mx+ny=17-------------- (ii)
nx + my = 15---------- (iii)
Adding (ii) and (iii), we get mx+ny+nx+my =17+15 ^ (m + n) x (x+y) = 32 ^ m + n = 32/40 as x+y =40.
Thus, m+n = 80 paise, hence b.
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Most Upvoted Answer
A man purchased 40 fruits; apples and oranges for Rs 17. Had he purcha...
Let's assume that the cost of an apple is 'x' and the cost of an orange is 'y'.

According to the given information, the man purchased a total of 40 fruits for Rs 17. Therefore, we can form the equation:

x + y = 17 --(1)

It is also given that if the man had purchased an equal number of oranges and apples, and the number of fruits is equal to 40, then he would have paid Rs 15. Forming another equation:

2x = 15 --(2)

Now, let's solve these equations to find the values of x and y.

Substituting the value of 2x from equation (2) into equation (1), we get:

15 + y = 17

Simplifying the equation:

y = 17 - 15
y = 2

Now, substituting the value of y into equation (1), we get:

x + 2 = 17

Simplifying the equation:

x = 17 - 2
x = 15

Therefore, the cost of one apple is Rs 15 and the cost of one orange is Rs 2.

To find the cost of one pair of an apple and an orange, we add the cost of one apple and one orange:

15 + 2 = 17

Hence, the cost of one pair of an apple and an orange is Rs 17.

But the options provided do not match the calculated value. So, let's try to find the mistake.

Mistake: The equations formed above are incorrect.

Correct equations:

Let's assume the number of apples purchased is 'a' and the number of oranges purchased is 'o'.

According to the given information, the man purchased a total of 40 fruits for Rs 17. Therefore, we can form the equation:

a + o = 40 --(3)

It is also given that if the man had purchased an equal number of oranges and apples, and the number of fruits is equal to 40, then he would have paid Rs 15. Forming another equation:

2a = 15 --(4)

Now, let's solve these equations to find the values of a and o.

Substituting the value of 2a from equation (4) into equation (3), we get:

15 + o = 40

Simplifying the equation:

o = 40 - 15
o = 25

Now, substituting the value of o into equation (3), we get:

a + 25 = 40

Simplifying the equation:

a = 40 - 25
a = 15

Therefore, the man purchased 15 apples and 25 oranges.

To find the cost of one pair of an apple and an orange, we need to find the cost of 1 apple and 1 orange.

The total cost of apples is 15 * x (where x is the cost of one apple).

The total cost of oranges is 25 * y (where y is the cost of one orange).

According to the given information, the total cost of 40 fruits is Rs 17. Therefore, we can form the equation:

15x + 25y = 17 --(5)

It is also given that if the man had purchased an equal number of oranges and apples, and the number of fruits is equal
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A man purchased 40 fruits; apples and oranges for Rs 17. Had he purchased as many as oranges as apples and as many apples as oranges, he would have paid Rs 15. Find the cost of one pair of an apple and an orange.a)70 paiseb)80 paisec)90 paised)Rupee 1Correct answer is option 'B'. Can you explain this answer?
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