Two pipes A and B can fill a tank in 12 hours and 18 hours respectivel...
Work done by the two pipes in 1 hour = (1/12)+(1/18) = (15/108).
Time taken by these pipes to fill the tank = (108/15)hrs = 7 hours 12 min.
Due to leakage, time taken to fill the tank = 7 hours 12 min + 48 min = 8 hours
Work done by two pipes and leak in 1 hour = 1/8.
Work done by the leak in 1 hour =(15/108)-(1/8)=(1/72).
Leak will empty the full cistern in 72 hours.
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Two pipes A and B can fill a tank in 12 hours and 18 hours respectivel...
Quantity I: Due to leakage, time taken to fill the tank
Let the capacity of the tank be C.
Pipe A can fill the tank in 12 hours, so in 1 hour it can fill 1/12th of the tank.
Pipe B can fill the tank in 18 hours, so in 1 hour it can fill 1/18th of the tank.
When both pipes are opened together, they can fill the tank in x hours. So, in 1 hour, they can fill 1/xth of the tank.
Using the formula, Work = Rate x Time, we can write:
Work done by pipe A in x hours = (1/12) * x
Work done by pipe B in x hours = (1/18) * x
Work done by both pipes in x hours = (1/x) * x = 1
But due to leakage, the tank is filled in (x + 48/60) hours. So, we can write:
(1/12) * x + (1/18) * x = 1 * (x + 48/60)
Simplifying this equation, we get:
x = 16
So, the tank can be filled in 16 hours when both pipes are open and there is leakage. But we need to find the time taken to fill the tank due to leakage, which is 48 minutes (or 0.8 hours).
Therefore, Quantity I is 0.8 hours.
Quantity II: Time taken to empty the full cistern
This quantity is not related to the given information and cannot be determined from the given data.
Hence, the answer is (a) Quantity I.