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Find the roots of the quadratic equation: x2 + 2x - 15 = 0?
- a)-5, 3
- b)3, 5
- c)-3, 5
- d)-3, -5
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
Find the roots of the quadratic equation: x2+ 2x - 15 = 0?a)-5, 3b)3, ...
Solution:
The given quadratic equation is x^2 + 2x - 15 = 0.
To find the roots of the quadratic equation, we can use the quadratic formula which is given as:
x = (-b ± √(b^2 - 4ac)) / 2a
where a, b, and c are the coefficients of the quadratic equation.
By comparing the given quadratic equation with ax^2 + bx + c = 0, we can see that a = 1, b = 2, and c = -15.
Substituting these values in the quadratic formula, we get:
x = (-2 ± √(2^2 - 4(1)(-15))) / 2(1)
x = (-2 ± √(64)) / 2
x = (-2 ± 8) / 2
Therefore, the roots of the quadratic equation are:
x = (-2 + 8) / 2 = 3
x = (-2 - 8) / 2 = -5
Hence, the correct answer is option A, which is -5 and 3.
The given quadratic equation is x^2 + 2x - 15 = 0.
To find the roots of the quadratic equation, we can use the quadratic formula which is given as:
x = (-b ± √(b^2 - 4ac)) / 2a
where a, b, and c are the coefficients of the quadratic equation.
By comparing the given quadratic equation with ax^2 + bx + c = 0, we can see that a = 1, b = 2, and c = -15.
Substituting these values in the quadratic formula, we get:
x = (-2 ± √(2^2 - 4(1)(-15))) / 2(1)
x = (-2 ± √(64)) / 2
x = (-2 ± 8) / 2
Therefore, the roots of the quadratic equation are:
x = (-2 + 8) / 2 = 3
x = (-2 - 8) / 2 = -5
Hence, the correct answer is option A, which is -5 and 3.
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Community Answer
Find the roots of the quadratic equation: x2+ 2x - 15 = 0?a)-5, 3b)3, ...
The given quadratic equation is x2 +2x - 15=0
This can be resolved as...
x2-3x+5x-15=0
x(x-3)+5(x-3) = 0
x-3=0 or x+5=0
x=3 or x=(-5)
Hope it will help!
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Find the roots of the quadratic equation: x2+ 2x - 15 = 0?a)-5, 3b)3, 5c)-3, 5d)-3, -5Correct answer is option 'A'. Can you explain this answer?
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