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The cut off wavelength of the rectangular waveguide in dominant mode with dimensions 6 cm x 4 cm is
- a)12cm
- b)6cm
- c)4cm
- d)2cm
Correct answer is option 'A'. Can you explain this answer?
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The cut off wavelength of the rectangular waveguide in dominant mode w...
Answer: a
Explanation: The cut off wavelength in the dominant mode is given by λc = 2a/m, where a is the broad wall dimension. On substituting for m = 1 and a = 6cm, we get the cut off wavelength as 12cm.
Explanation: The cut off wavelength in the dominant mode is given by λc = 2a/m, where a is the broad wall dimension. On substituting for m = 1 and a = 6cm, we get the cut off wavelength as 12cm.
Most Upvoted Answer
The cut off wavelength of the rectangular waveguide in dominant mode w...
The cut-off wavelength of a rectangular waveguide in the dominant mode can be determined using the formula:
λc = 2 * a / √(m^2 / b^2 + n^2 / d^2)
where:
λc is the cut-off wavelength
a is the width of the waveguide
b is the height of the waveguide
m and n are the mode numbers
d is the dominant mode number
In this case, the given dimensions of the rectangular waveguide are 6 cm x 4 cm.
Let's calculate the cut-off wavelength using the formula above.
1. Identify the given values:
a = 6 cm
b = 4 cm
2. Determine the mode numbers:
In the dominant mode, the mode numbers are given by:
m = 1
n = 0
3. Calculate the cut-off wavelength:
λc = 2 * 6 cm / √(1^2 / 4^2 + 0^2 / 6^2)
= 12 cm / √(1/16 + 0/36)
= 12 cm / √(1/16)
= 12 cm / (1/4)
= 12 cm * 4
= 48 cm
Therefore, the cut-off wavelength of the rectangular waveguide with dimensions 6 cm x 4 cm in the dominant mode is 48 cm.
In the given options:
a) 12 cm
b) 6 cm
c) 4 cm
d) 2 cm
The correct answer is option A, 12 cm, as calculated above.
λc = 2 * a / √(m^2 / b^2 + n^2 / d^2)
where:
λc is the cut-off wavelength
a is the width of the waveguide
b is the height of the waveguide
m and n are the mode numbers
d is the dominant mode number
In this case, the given dimensions of the rectangular waveguide are 6 cm x 4 cm.
Let's calculate the cut-off wavelength using the formula above.
1. Identify the given values:
a = 6 cm
b = 4 cm
2. Determine the mode numbers:
In the dominant mode, the mode numbers are given by:
m = 1
n = 0
3. Calculate the cut-off wavelength:
λc = 2 * 6 cm / √(1^2 / 4^2 + 0^2 / 6^2)
= 12 cm / √(1/16 + 0/36)
= 12 cm / √(1/16)
= 12 cm / (1/4)
= 12 cm * 4
= 48 cm
Therefore, the cut-off wavelength of the rectangular waveguide with dimensions 6 cm x 4 cm in the dominant mode is 48 cm.
In the given options:
a) 12 cm
b) 6 cm
c) 4 cm
d) 2 cm
The correct answer is option A, 12 cm, as calculated above.
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