Present age of Husband and Wife is 28 and 24 Years respectively. At th...
28+24/2 =26 = (28+x+24+x+2x)/4
104 = (52+4x)
x= 13
Present age of Husband and Wife is 28 and 24 Years respectively. At th...
Solution:
Let's assume that the family had n members before the babies were born. Therefore, the average age of the family was (28n + 24n)/n = 52 years.
After the twins were born, the family size increased by 2, and the total age of the family increased by 2 × 0 = 0 years (since the babies were just born and had age 0). Therefore, the new average age of the family is:
(28n + 24n + 0) / (n + 2) = (52n + 0) / (n + 2) = (52n / (n + 2))
We want to find after how many years the average age of the family will be the same as before the babies were born. Let's assume that the family will take x years to reach this point.
After x years, the husband will be 28 + x years old, the wife will be 24 + x years old, and the twins will be x years old. Therefore, the sum of the ages of the family members will be:
(28 + x) + (24 + x) + x + x = 52 + 3x
The family size will still be n + 2 since the twins will still be part of the family. Therefore, the average age of the family after x years will be:
(52 + 3x) / (n + 2)
We want this average age to be equal to 52, which was the average age before the babies were born. Therefore, we can write:
(52 + 3x) / (n + 2) = 52
Solving for x, we get:
x = (n + 2) / 3
Therefore, x will be an integer if (n + 2) is divisible by 3. Since we don't know the value of n, we cannot determine whether x will be an integer or not. Therefore, the answer is (e) cannot be determined.