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A train running with 72km/hr takes 20sec to cross a platform 200 m long. How much it takes to cross a stationary train having twice the length of platform.
  • a)
    20 sec
  • b)
    30 sec
  • c)
    40 sec
  • d)
    50 sec
  • e)
    None of these
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A train running with 72km/hr takes 20sec to cross a platform 200 m lon...
200+L =  72*(5/18)*20. L= 200m.
400 + 200 = 72*(5/18)*t. So, t = 30sec
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Most Upvoted Answer
A train running with 72km/hr takes 20sec to cross a platform 200 m lon...
Given:

Speed of train (s) = 72 km/hr

Length of platform (l) = 200 m

To find:

Time taken to cross a stationary train having twice the length of the platform.

Solution:

1. First, let's convert the speed of the train from km/hr to m/s.

We know that,

1 km/hr = 5/18 m/s

Therefore, speed of the train (s) = 72 × 5/18 = 20 m/s

2. Now, let's find the time taken by the train to cross the platform.

We know that,

Speed = Distance/Time

Therefore, Time taken to cross the platform = Distance/Speed

Time taken to cross the platform = 200/20 = 10 seconds

3. Let's find the length of the stationary train.

We know that,

Time taken to cross a stationary object = Length of train + Length of platform / Speed

Therefore, Length of stationary train = Speed × Time taken to cross a stationary object - Length of platform

Length of stationary train = 20 × (10 + 20) - 200

Length of stationary train = 400 m

4. Now, let's find the time taken by the train to cross the stationary train.

We know that,

Time taken to cross a stationary object = Length of train + Length of platform / Speed

Therefore, Time taken to cross the stationary train = (2 × 200 + 400) / 20

Time taken to cross the stationary train = 30 seconds

Hence, the correct answer is option (b) 30 seconds.
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