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Two cities A and B are at a distance of 120 km from each other. Two persons P and Q start from First city at a speed of 20km/hr and 10km/hr respectively. P reached the second city B and returns back and meets Q at Y. Find the distance between A and Y.
  • a)
    50 km
  • b)
    66 km
  • c)
    55 km
  • d)
    40 km
  • e)
    None of these
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Two cities A and B are at a distance of 120 km from each other. Two pe...
Given, distance between cities A and B = 120km
Speed of person P = 20km/hr
Speed of person Q = 10km/hr

Let's assume that the meeting point Y is at a distance of x km from city A.

Time taken by person P to reach city B and come back to Y =
(distance from A to B + distance from B to Y) / speed =
(120 + x*2) / 20 = (120 + 2x) / 20

Time taken by person Q to reach Y =
distance from A to Y / speed =
x / 10

Since both persons meet at Y, they must have taken the same amount of time to reach there.

Therefore, (120 + 2x) / 20 = x / 10
Simplifying the above equation, we get:
6x = 120
x = 20

Hence, the distance between A and Y is 20km.

Therefore, the correct answer is option D) 40km.
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Two cities A and B are at a distance of 120 km from each other. Two persons P and Q start from First city at a speed of 20km/hr and 10km/hr respectively. P reached the second city B and returns back and meets Q at Y. Find the distance between A and Y.a)50 kmb)66 kmc)55 kmd)40 kme)None of theseCorrect answer is option 'D'. Can you explain this answer?
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